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Marianna [84]
3 years ago
14

What is the relationship between the frequency and the pitch of a sound?

Physics
2 answers:
Reika [66]3 years ago
7 0

Answer:

The Correct Answer is C

Explanation:

The association between pitch and frequency.

  • The pitch of a sound you detect relies on the repetition of the sound wave.
  • A greater-frequency sound wave has a great pitch, and a lower-frequency sound wave has a lowering pitch.
  • The frequency of a sound wave is the number of fluctuations that happen per moment.
  • The pitch of a sound is a representation of how great or below the sound appears to a person.

andrezito [222]3 years ago
3 0
Choice-C is the correct one.
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The average speed of a greyhound bus from lansing to detroit is 104.5 km/h. on the return trip from detroit to lansing the avera
Nitella [24]
The average speed of the bus from Lansing to Detroit is 
v_1 = 104.5 km/h
while the average speed of the bus from Detroit to Lansing is
v_2 =56.2 km/h

The distance covered by the bus in the two trips is the same (the distance between the two cities), therefore, the average speed of the round trip can be calculated as the mean of the two speeds:
v= \frac{v_1+v_2}{2}= \frac{104.5+56.2}{2}=80.35 km/h
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3 years ago
5. A box weighs 196 N. A rope is tied to the box. What is the
natta225 [31]

Answer:

296 N

Explanation:

Draw a free body diagram.  The box has two forces on it: tension up and weight down.

Apply Newton's second law:

∑F = ma

T − mg = ma

T = m (g + a)

Given m = 196 N / 9.8 m/s² = 20 kg, and a = +5 m/s²:

T = (20 kg) (9.8 m/s² + 5 m/s²)

T = 296 N

5 0
2 years ago
Pyramid math (algebra 1)
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3 0
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Convection requires______to transfer heat.
mylen [45]
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6 0
2 years ago
Question 9 In an RC series circuit, ε = 12.0 V, R = 1.07 MΩ, and C = 2.66 µF. (a) Calculate the time constant. (b) Find the maxi
meriva

Answer:

a.) τ = 2.85 s b.) Q = 3.19 * 10^-5 C c.) t = 1.691 s

Explanation:

So we are told that it is a RC circuit. We are told Q = C V [1 - e^(-t/RC)] = 12.0 V, R =  1.07 MΩ and C = 2.66 µF.

a.) The time constant for RC circuit, τ = RC. Substituting our known values we get:

τ = RC where R = (1.07 * 10 ^ 6)Ω and C = (2.66 * 10 ^ -6) F

τ = (1.07 * 10 ^ 6)Ω * (2.66 * 10 ^ -6) F = 2.8462 s ≈ 2.85 s

τ = 2.85 s

b.) The relationship between capacitance, potential, charge is given:

Q = CV[1-e^{-t/RC} ]

The capacitor is fully charge when t approaches infinity, therefore:

Q =  \lim_{t \to \infty} a_n CV[1-e^{-t/RC} ]

When t approaches infinity, the term e becomes very small (e^-∞ = 0), therefore we can simplify the equation and plug in our values

Q = (2.66*10^{-6}) F * (12.0)V *[1 - 0] = 3.192 * 10^{-5}

Q = 3.19 * 10^-5 C

c.) Using the same equation as before, we can substitute Q in and solve for Q:

(14.3 * 10 ^ 6) C = (2.66*10^{-6})F *(12.0)V*[1-e^{-t/(2.85s)}]\\0.552 = e^{-t/(2.85s)}\\t = -1 * 2.85 * ln(0.552) \\t = 1.69120678 s

t = 1.691 s

Hope this helps! I'm not sure what the units you want, so convert to the desired units.

6 0
3 years ago
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