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zhenek [66]
3 years ago
10

A particle moving with initial velocity of 5m/s is subjected to a uniform acceleration of -2.5 m/s2.find the displacement for ne

xt 4 second
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0
1/2vt^2-1/2at^2
1/2*5*16-1/2*2,5*16=20
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describe the forces acting on a car as it movies along a level highway in still air at a constant speed
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The car's forward motion is opposed by the friction between the road and the tires and by the resistance of the air.

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2 years ago
What's the airplane velocity when it flies 100 miles in 20 seconds<br><br>​
Allushta [10]

Answer : 5m/s

Explanation:the formular for velocity is distance /time or you can say displacement /time. Then it would then be

100/20 =5m/s

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3 years ago
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Your brother is insisting that you’ll never hear a sound produced behind a barrier wall at the end of your yard you notice that
Tresset [83]

Answer

D.Diffraction

Explanation

Diffraction is a property that is experienced by waves when they come across a barrier when they are in motion.

The ways tends to curve behind the barrier. This is called diffraction of waves.

Now, sound is a wave and it also experience diffraction. . So the brother will be able to hear the sound due to diffraction

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3 years ago
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An airplane is moving at 350 km/hr. If a bomb is
bogdanovich [222]

Answers:

a) -171.402 m/s  

b) 17.49 s

c) 1700.99 m

Explanation:

We can solve this problem with the following equations:

y=y_{o}+V_{oy}t-\frac{1}{2}gt^{2} (1)

x=V_{ox}t (2)

V_{f}=V_{oy}-gt (3)

Where:

y=0 m is the bomb's final height

y_{o}=1.5 km \frac{1000 m}{1 km}=1500 m is the bomb's initial height

V_{oy}=0 m/s is the bomb's initial vertical velocity, since the airplane was moving horizontally

t is the time

g=9.8 m/s^{2} is the acceleration due gravity

x is the bomb's range

V_{ox}=350 \frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=97.22 m/s is the bomb's initial horizontal velocity

V_{f} is the bomb's final velocity

Knowing this, let's begin with the answers:

<h3>b) Time </h3>

With the conditions given above, equation (1) is now written as:

y_{o}=\frac{1}{2}gt^{2} (4)

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (5)

t=\sqrt{\frac{2 (1500 m)}{9.8 m/s^{2}}} (6)

t=17.49 s (7)

<h3>a) Final velocity </h3>

Since V_{oy}=0 m/s, equation (3) is written as:

V_{f}=-gt (8)

V_{f}=-(97.22)(17.49 s) (9)

V_{f}=-171.402 m/s (10) The negative sign only indicates the direction is downwards

<h3>c) Range </h3>

Substituting (7) in (2):

x=(97.22 m/s)(17.49 s) (11)

x=1700.99 m (12)

5 0
3 years ago
How does the amount of precipitation affect the amount of weathering ?
4vir4ik [10]

Answer: Rainfall and temperature can affect the rate in which rocks weather. High temperatures = more rainfall increasing the rate of chemical weathering. Rocks in tropical regions exposed to a lot of rainfall and hot temperatures weather faster than similar rocks in cold, dry climates.

Explanation:

7 0
3 years ago
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