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3 years ago

10

A particle moving with initial velocity of 5m/s is subjected to a uniform acceleration of -2.5 m/s2.find the displacement for ne

xt 4 second

1 answer:

LUCKY_DIMON [66]3 years ago

6 0

1/2vt^2-1/2at^2
1/2*5*16-1/2*2,5*16=20

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Are materials that dissolve in water hydrophobic or hydrophilic

stira [4]

Answer:

hydrophilic

Explanation:

hydrophobic means it hates water so a hydrophobic material would separate from the water and just sit there (an example of this is oil)

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3 years ago

Read 2 more answers

What is the displacement of the object from 12 seconds to 16 seconds

spayn [35]

Answer:

<em>The displacement of the object is -8 m</em>

Explanation:

<u>Displacement</u>

The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.

If the area is below the y-axis, then the displacement is negative. Otherwise is positive.

It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.

From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.

The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

$\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m$

The displacement of the object is -8 m

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3 years ago

If a rock is thrown upward on the planet Mars with a velocity of 10 m/s, its height in meters t seconds later is given by y= 10t

spin [16.1K]

Answer:

a)

i) v = 4.42 m/s

ii) v = 5.36 m/s

iii) v = 6.1 m/s

iv) v = 6.26 m/s

v) v = 6.28 m/s

b) The instantaneous velocity at t = 1 is 6.28 m/s

Explanation:

a) The average velocity is the variation of the position over time. It is expressed as follows:

v = Δy/Δt

Where

v = average velocity

Δy = displacement = final position - initial position

Δt = variation of time = final time - initial time

i) Let´s find the position at both times and then apply the equation for the average velocity:

y(t) = 10 · t - 1.86 · t²

y(1 s) = 10 m/s · 1 s - 1.86 m/s² · (1 s)²

y = 8.14 m

y (2 s) = 10 m/s · 2 s - 1.86 m/s² · (2 s)²

y = 12.56 m

Then, the average velocity will be:

v = final position - initial position / final time - initial time

v = 12.56 m - 8.14 m / 2 s - 1 s = 4.42 m/s

ii) We proceed in the same way as in i)

y(1.5 s) = 10 m/s · 1.5 s - 1.86 m/s² · (1.5 s)²

y = 10.82 m

v = 10.82 m - 8.14 m / 1.5 s - 1 s = 5.36 m/s

iii)

y(1.1 s) = 10 m/s · 1.1 s - 1.86 m/s² · (1.1 s)²

y = 8.75 m

v = 8.75 m - 8.14 m / 1.1 s - 1 s = 6.1 m/s

iv)

y(1.01 s) = 10 m/s · 1.01 s - 1.86 m/s² · (1.01 s)²

y = 8.20 m

v = 8.20 m - 8.14 m / 1.01 s - 1 s = 6 m/s ( 6.26 m/s without rounding the y-final value)

v)

y(1.001 s) = 10 m/s · 1.001 s - 1.86 m/s² · (1.001 s)²

y = 8.146

v = 8.146 m - 8.14 m / 1.001 s - 1 s = 6 m/s (6.28 m/s without rounding the value of y-final)

b) The instantaneous velocity is given by the derivative of the position function:

y = 10 · t - 1.86 · t²

dy/dt = 10 - 2 · 1.86 · t = 10 - 3.72 · t

At t = 1

v = 10 m/s - 3.72 m/s² · 1 s = 6.28 m/s

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3 years ago

What is another word for cycles per second??

Hatshy [7]

Frequensey or hertz, I looked this up on the internet!

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A double slit has a slit separation of 2.02 x 10-6 m, and the first bright fringe of a light is seen at an angle of 16.5º relati

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The answer would be <span>B. 574 nm</span>

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