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telo118 [61]
3 years ago
14

I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER! Fill in the blanks

Physics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

See the explanation below.

Explanation:

<u>meters</u> per <u>second</u> per <u>second</u> = (m/s/s) = (m/s^2)

This means that the body increases or decreases its speed 1 (m/s), for every second that passes. An easy example to understand is the acceleration of gravity g = 10 [m/s^2]. This means that if a body is thrown from a 100 (m) high tower, for every second it passes the speed will increase by 10 [m/s].

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on the surface of jupiter the acceleration due to gravity is about 3 times that on earth. how much would a 100kg rock weigh on j
madam [21]

Answer:

Weight on Jupiter will be equal to 2940 N

Explanation:

We have given given acceleration due to gravity on Jupiter is 3 times of acceleration due to gravity on earth

Acceleration due to gravity on earth g=9.8m/sec^2

So acceleration due to gravity on Jupiter = g'=3\times 9.8=29.4m/sec^2

Mass is given m = 100 kg

We have to find the weight

Weight is equal to W = mg, here m is mass and a is acceleration

So weight W=100\times 29.4=2940N

4 0
3 years ago
Read 2 more answers
Cars A and B are racing each other along the same straight road in the following manner:
zysi [14]

Answer:

\frac{x_{o}}{v_B-V_A} =t

Explanation:

Represent the car's position as a function

x_o= "head start"

x_{A}(t) = x_{o} + v_{A}t\\x_B(t)=v_Bt \\

Remember: v_B>v_A

"cathching up means" that x_A(t)=x_B(t)

x_{o} + v_{A}t =v_Bt\\x_{o} = v_Bt -v_{A}t\\x_{o} = t(v_B-V_A)\\\frac{x_{o}}{v_B-V_A} =t, where \ v_B>v_A

8 0
3 years ago
What device increases voltage?
erma4kov [3.2K]

Your answer would be C.

A step-up transformer is a transformer that raises voltage from main to secondary by having more secondary winding turns than primary winding turns.

Hope this helps; have a great day!

8 0
3 years ago
2 Which is true of a parallel circuit?
mars1129 [50]

Answer:

fxb

c

Explanation:bfffffffff

8 0
3 years ago
Two Polaroids are aligned so that the initially unpolarized light passing through them is a maximum. At what angle should one of
steposvetlana [31]

To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.

Mathematically the expression is given as

I = I_0 cos^2\theta

Where,

I_0= Initial Intensity

I = Final Intensity after pass through the polarizer

\theta= Angle between the polarizer and the light

Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as

\frac{I}{I_0} = \frac{1}{2}

Using the Malus Law we have,

I = I_0 cos^2\theta

cos^2\theta = \frac{I}{I_0}

cos^2\theta = \frac{1}{2}

\theta = cos^{-1}(\frac{1}{2})^2

\theta = 75.52\°

Angle with respect to maximum is 90-75.52 = 14.48\°

8 0
3 years ago
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