It even and equally distributes the heat, therefore giving the food a more thorough cook in the microwave compared to one without a turntable.
Answer:
it could be a B. egg cell or C. A stem cell but im pretty sure the answer is egg cell
hopes it helps!
Carbon
calcuim
iron
hydrogen
iodine
nitrogen
oxygen
phosphorus
sulfur
The letters are the symbols for those elements
Answer:
Balanced chemical equation:
Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃
Explanation:
When potassium iodide react with lead(II) nitrate, lead iodide is produced and solution of potassium nitrate also formed. The lead iodide is produced in the form yellow precipitate.
Chemical equation:
Pb(NO₃)₂ + KI → PbI₂ + KNO₃
Balanced equation:
Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃
The equation is balanced because there are one lead atom, two nitrate, two potassium and two iodide atoms are on both side of equation.
Word equation:
Lead nitrate + potassium iodide → lead iodide + potassium nitrate
Answer: The standard enthalpy change for this reaction is -116 kJ
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction is,
![2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)](https://tex.z-dn.net/?f=2H_2CO%28g%29%5Crightarrow%202C%28s%2C%20graphite%29%2B2H_2%28g%29%2BO_2%28g%29)
![\Delta H^0=232KJ](https://tex.z-dn.net/?f=%5CDelta%20H%5E0%3D232KJ)
Now we have to determine the value of
for the following reaction i.e,
![\Delta H^0'=?](https://tex.z-dn.net/?f=%5CDelta%20H%5E0%27%3D%3F)
According to the Hess’s law, if we reverse the reaction then the
will change its sign and if we half the reaction, then the
So, the value
for the reaction will be:
![\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5E0%27%3D%5Cfrac%7B%28-232kJ%2Fmole%29%7D%7B2%7D%3D-116kJ)
Hence, the standard enthalpy change for this reaction is -116 kJ