All categories

3 years ago

1.Write out the net equation for the dissolution of the ionic compound KNO3.

Chemistry

1 answer:

frosja888 [35]3 years ago

4 0

Answer:

1. KNO3(s) ------> K^+(aq) + NO3^-(aq)

2. The dissolution is endothermic

3. The sign of the enthalpy of dissolution is positive

Explanation:

The sign of the enthalpy of dissolution depends on the hydration energy and the lattice energy.

For KNO3, the hydration energy is less than the lattice energy hence the dissolution is endothermic and the enthalpy of dissolution is positive.

You might be interested in

Which characteristics can be inherited

andre [41]

Answer:

skin color, personality type, hair color/type, eye shape/type chin type, face shape etc.

Explanation:

hope this helps!

5 0

3 years ago

Read 2 more answers

Hazmat Poison gas is in what class?

Alik [6]

HAZMAT Class 6 Toxic and infectious substances.

8 0

2 years ago

Read 2 more answers

Answer fast my H.W is hard

Marina86 [1]

<u>Answer:</u> The molality of $MgF_2$ solution is 4.013 m

<u>Explanation:</u>

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg.

The formula used to calculate molarity:

.....(1)

Given values:

Given mass of $MgF_2$ = 20.0 g

Molar mass of = 62.3 g/mol

Mass of solvent = 80.0 g

Putting values in equation 1, we get:

$\text{Molality of }MgF_2=\frac{20.0\times 1000}{62.3\times 80.0}\\\\\text{Molality of }MgF_2=4.013m$

Hence, the molality of $MgF_2$ solution is 4.013 m

3 0

3 years ago

Can someone help me!!

Art [367]

Idk but here something that made my day

8 0

4 years ago

The reaction of solid aluminum with hydrochloric acid is used to make hydrogen gas in a laboratory experiment. The reaction is 2

Gemiola [76]

Answer:

0.003088 moles of hydrogen gas were formed .

Explanation:

Pressure at which hydrogen gas is collected at 20°C = 768.0 Torr

Vapor pressure of water at 20°C = 17.5 Torr

Total pressure = Vapor pressure of water + Partial pressure of hydrogen gas

Partial pressure of hydrogen gas:

Total pressure - Vapor pressure of water

= 768.0 Torr - 17.5 Torr = 750.5 Torr = 0.987 atm

(1 Torr = 0.001315 atm)

Pressure of hydrogen gas =P = 0.986 atm

Temperature at which gas was collected ,T= 20°C = 293.15 K

Volume of the gas ,V= 75.3 mL = 0.0753 L

Moles of hydrogen gas = n

PV=nRT (An ideal gas equation)

$n=\frac{PV}{RT}=\frac{0.987 atm\times 0.0753 L}{0.0821 atm L/mol K\times 293.15 K}=0.003088 mol$

0.003088 moles of hydrogen gas were formed .

7 0

4 years ago