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SVETLANKA909090 [29]
4 years ago
9

Potassium Iodide + Lead Nitrate products

Chemistry
1 answer:
nika2105 [10]4 years ago
5 0

Answer:

Balanced chemical equation:

Pb(NO₃)₂  + 2KI → PbI₂ + 2KNO₃

Explanation:

When potassium iodide react with lead(II) nitrate, lead iodide is produced and solution of potassium nitrate also formed. The lead iodide is produced in the form yellow precipitate.

Chemical equation:

Pb(NO₃)₂  + KI → PbI₂ + KNO₃

Balanced equation:

Pb(NO₃)₂  + 2KI → PbI₂ + 2KNO₃

The equation is balanced because there are one lead atom, two nitrate, two potassium and two iodide atoms are on both side of equation.

Word equation:

Lead nitrate + potassium iodide → lead iodide + potassium nitrate

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C) a log in the campfire turns into ashes

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How many moles in 44.7 kg of carbon dioxide
slava [35]

Answer:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

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7 0
2 years ago
How many grams of iron can be made with 21.5g of Fe2O3
SIZIF [17.4K]

The mass (in grams) of iron, Fe that can be made from 21.5 g of Fe₂O₃ is 15.04 g

We'll begin by writing the balanced equation for the reaction. This is given below:

2Fe₂O₃ -> 4Fe + 3O₂

  • Molar mass of Fe₂O₃ = 159.7 g/mol
  • Mass of Fe₂O₃ from the balanced equation = 2 × 159.7 = 319.4 g
  • Molar mass of Fe = 55.85 g/mol
  • Mass of Fe from the balanced equation = 4 × 55.85 = 223.4 g

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

<h3>How to determine the mass of iron, Fe produced</h3>

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

Therefore,

21.5 g of Fe₂O₃ will decompose to produce = (21.5 × 223.4) / 319.4 = 15.04 g of Fe

Thus, 15.04 g of Fe were produced.

Learn more about stoichiometry:

brainly.com/question/9526265

#SPJ1

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1 year ago
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