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topjm [15]
4 years ago
9

Phospholipids, molecules found within a cell membrane, have hydrophobic tails and hydrophilic heads. These regions act in the sa

me manner that hydrophobic and hydrophilic amino acids act. When phospholipids are found as a sphere in a glass of water, which of the following would you expect?
a. The hydrophobic tails will point toward the water, and the hydrophilic heads will point away from the water.
b. The hydrophilic heads will point toward the water, and the hydrophobic tails will point away from the water.
c. Hydrophilic heads and hydrophobic tails will both point toward the water.
d. The hydrophobic tails and hydrophilic heads will be arranged randomly.
Chemistry
1 answer:
JulsSmile [24]4 years ago
3 0

Answer:

B

Explanation:

When a phospholipid is found in a sphere of water, the hydrophilic head is expected to point towards the water while the hydrophobic tail will point away from the water.

The term hydrophilic means water loving, So it is expected that the hydrophilic head will move towards water molecules at it has affinity for water molecules.

The opposite is the case for the hydrophobic tail. The hydrophobic tail moves away from water molecules

What these cases suggest is that both regions are acting base on their chemical make up. While the hydrophilic head contains molecules which are capable of interacting and bonding with water molecules, the hydrophobic tail contains strictly non polar molecules which are not capable of water interaction. Hence the interactions a phospholipid has with water is through its head region

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Answer:

Ha is more acidic than Hb because loss of Ha forms a resonance-stabilized conjugate base.

Explanation:

The carbon atom that is next to the carbonyl group in pentan-2-one is known as the alpha carbon atom, this carbon atom bears the Ha, the alpha hydrogen atoms.

Ha is more acidic than Hb because, loss of Ha leads to the formation of a resonance stabilized enolate ion. This resonance stabilization of the ion formed makes loss of Ha an easier process than loss of Hb, hence the answer above.

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Answer:

F2 is the limiting reactant

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Explanation:

Balance the equation first.

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12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

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Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

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