Answer:
k ≈ 9,56x10³ s⁻¹
Explanation:
It is possible to solve this question using Arrhenius formula:
Where:
k1: 1,35x10² s⁻¹
T1: 25,0°C + 273,15 = 298,15K
Ea = 55,5 kJ/mol
R = 8,314472x10⁻³ kJ/molK
k2 : ???
T2: 95,0°C+ 273,15K = 368,15K
Solving:
<em>k ≈ 9,56x10³ s⁻¹</em>
I hope it helps!
Answer:
We can solve this by the method of which i solved your one question earlier
so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372
which is almost = 41.26 moles
so to get one mole of C12H25NaSO4 we need one mole of C12H26O
so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O
so the mass of C12H26O = 41.26× its molar mass
C12H26O = 41.26×186.34
= 7688.38 gm!!
so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!
Again i d k wether it's right or wrong but i tried my best hope it helped you!!
Answer:
The answer is B. False
Explanation:
The ratio of sizes between the ionic radii of cations and anions in a cell influences the manner of packing for that cell thereby predicting the possible cation/anion coordination number in any compound and establishing the structure of ionic solids.
Answer:
CO + 2H2 = CH3OH
Explanation:
1. Label Each Compound With a Variable
aCO + bH2 = cCH3OH
2. Create a System of Equations, One Per Element
C: 1a + 0b = 1c
O: 1a + 0b = 1c
H: 0a + 2b = 4c
3. Solve For All Variables (using substitution, gauss elimination, or a calculator)
a = 1
b = 2
c = 1
4. Substitute Coefficients and Verify Result
CO + 2H2 = CH3OH
L R
C: 1 1 ✔️
O: 1 1 ✔️
H: 4 4 ✔️
