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Nutka1998 [239]
3 years ago
10

I need help asaaaaap

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

NOT APPLICABLE

Explanation:

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Nata [24]

Answer:

people who think that their child would be happy for life

Explanation:

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Name two metalloids that are semiconductors
guajiro [1.7K]

The Metalloids are:

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3 years ago
An unknown diprotic acid (H2A) requires 44.391 mL of 0.111 M NaOH to completely neutralize a 0.58 g sample. Calculate the approx
Anna [14]

Answer:

M=235.42g/mol

Explanation:

Hello!

In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:

2n_{acid}=n_{base}

It means that the moles of acid can be computed given the volume and concentration of NaOH:

n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol

It means that the approximate molar mass of the acid is:

M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol

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5 0
3 years ago
PLS HELP ASAP!! Why is titanium known as a strategic metal??
Rom4ik [11]

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7 0
3 years ago
Find the normality of 0.321 g sodium carbonate in a 250 mL solution.
Radda [10]

Answer:

the normality of the given solution is 0.0755 N

Explanation:

The computation of the normality of the given solution is shown below:

Here we have to realize the two sodiums ions per carbonate ion i.e.

N = 0.321g Na_2CO_3 × (1mol ÷ 105.99g)×(2eq ÷ 1mol)

= 0.1886eq ÷ 0.2500L

= 0.0755 N

Hence, the normality of the given solution is 0.0755 N

5 0
3 years ago
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