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kondaur [170]
2 years ago
9

in the following reaction 10.5 moles of chromium are added to 6.8 moles of oxygen find limiting an excess reactants and answer t

he questions that follow.

Chemistry
1 answer:
drek231 [11]2 years ago
8 0

Answer:

If 3.4 moles of carbon dioxide (CO2) form at the end of the reaction, 1.7 moles of oxygen gas

(02) and 3.4 moles of carbon monoxide (CO) entered the reaction

Explanation:

The rule of three or is a way of solving problems of proportionality between three known

values and an unknown value, establishing a relationship of proportionality between all of

them. That is, what is intended with it is to find the fourth term of a proportion knowing the

other three. Remember that proportionality is a constant relationship or ratio between different

magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so

does the other (or when one magnitude decreases, so does the other), the direct rule of three

must be applied. To solve a direct rule of three, the following formula must be followed:

ab

cx

So

C*b

T =

a

In this case, it is possible to use the reaction stoichiometry of the reaction (that is, the

relationship between the amount of reagents and products in a chemical reaction) and the rule

of three to calculate the quantities of moles requested:

.

,

If by stoichiometry 2 moles of CO2 are formed by 1 mol of O2, if 3.4 moles of CO2 are

formed, how many moles of O2 are needed?

molesofo2 = 3.42

=

moles of O2=1.7 moles

• If by stoichiometry 2 moles of CO2 are formed by 2 moles of CO, if 3.4 moles of CO2 are

formed, how many moles of CO are needed?

molesof CO =

=

3.4*2

2

moles of CO=3.4

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no, not all objects emit electromagnet waves.

Explanation: because lets say the object is carpet it has no magnetic waves in it so not all objects do.

6 0
3 years ago
stbank, Question 075 Get help answering Molecular Drawing questions. Compound A, C6H12 reacts with HBr/ROOR to give compound B,
Law Incorporation [45]

Answer:

Explanation:

In this case we want to know the structures of A (C6H12), B (C6H13Br) and C (C6H14).

A and C reacts with two differents reagents and conditions, however both of them gives the same product.

Let's analyze each reaction.

First, C6H12 has the general formula of an alkene or cycloalkane. However, when we look at the reagents, which are HBr in ROOR, and the final product, we can see that this is an adition reaction where the H and Br were added to a molecule, therefore we can conclude that the initial reactant is an alkene. Now, what happens next? A is reacting with HBr. In general terms when we have an adition of a molecule to a reactant like HBr (Adding electrophyle and nucleophyle) this kind of reactions follows the markonikov's rule that states that the hydrogen will go to the carbon with more hydrogens, and the nucleophyle will go to the carbon with less hydrogen (Atom that can be stabilized with charge). But in this case, we have something else and is the use of the ROOR, this is a peroxide so, instead of follow the markonikov rule, it will do the opposite, the hydrogen to the more substituted carbon and the bromine to the carbon with more hydrogens. This is called the antimarkonikov rule. Picture attached show the possible structure for A. The alkene would have to be the 1-hexene.

Now in the second case we have C, reacting with bromine in light to give also B. C has the formula C6H14 which is the formula for an alkane and once again we are having an adition reaction. In this case, conditions are given to do an adition reaction in an alkane. bromine in presence of light promoves the adition of the bromine to the molecule of alkane. In this case it can go to the carbon with more hydrogen or less hydrogens, but it will prefer the carbon with more hydrogens. In this case would be the terminal hydrogens of the molecules. In this case, it will form product B again. the alkane here would be the hexane. See picture for structures.

8 0
3 years ago
Hello guys can you help me on this.​
RideAnS [48]

Answer:

1.Sulfur dioxide and nitrogen oxide

2.a)it forms carbonic acid

b)

3.the community can use renewable energy like solar and wind power cause they produce less pollution

5 0
3 years ago
Could someone help me balance this chemical equation please
Softa [21]
Balanced equation:
Ca(OH)2+H2SO4=CaSO4+2 H20<span />
4 0
2 years ago
Suppose that a heat engine operates with a hot source at a temperature of 485 oC and a cold sink at 42 oC. What is the maximum a
Marta_Voda [28]

Answer:

W = - 10.5943 KJ, work is negative because it is carried out by the system towards the surroundings.

Explanation:

heat engine:

∴ Th = 485°C

∴ Tc = 42°C

∴ Qh = 9.75 KJ......heat from hot source

first law:

∴ ΔU = Q + W = 0 .........cyclic process

⇒ Q = - W

∴ Q = Qh + Qc = Qh - (- Qc)

∴ Qc: heat from the cold source ( - )

⇒ Qh - ( - Qc) = - W..............(1)

⇒ Qc/Qh = - Tc/Th...........(2)

from (2):

⇒ Qc = - (Tc/Th)(Qh) = - (42°C/485°C)(9.75 KJ)

⇒ Qc = - 0.8443 KJ

replacing in (1):

⇒ - W = 9.75 KJ - ( - 0.8443 KJ)

⇒ - W = 10.5943 KJ

3 0
3 years ago
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