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2 years ago

How many moles of silver chloride, produced from 100 g of silver nitrate reacting with barium chloride BaCl2?

Chemistry

1 answer:

Dmitrij [34]2 years ago

7 0

Answer:

Equation of Reaction

2AgNO3 + BaCl2 === 2AgCl + Ba(NO3)2

Molar Mass of AgNO3 = 170g/mol

Moles of reacting AgNO3 = 100g/170gmol-¹

=0.588moles of AgNO3

From the equation of reaction...2moles of AgNO3 reacts to Produce 2Moles of Silver Chloride

So Their ratio is 2:2.

This means that 0.588Moles of AgCl Will be produced too.

ANSWER...0.588MOLES OF AgCl WILL BE PRODUCED.

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Why do you think the Na+ ion is smaller than a neutral Na atom? Why do you think the Cl - ion is larger than a neutral Cl atom?

Sphinxa [80]

Answer:

Na+ ion is smaller than a neutral Na atom in the ion there was one more proton which will attract electron bring it closer to the center making the atomic radius smaller. Therefore making a Na+ ion is smaller than a neutral Na atom Explanation:

yes

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2 years ago

Consider the following balanced equation:

algol [13]

Moles of PF₃ : 4

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

$\tt P_4(s)+6F_2(g)\rightarrow 4PF_3(g)$

1.25 moles of P₄(s) is reacted with 6 moles of F₂(g)

Limiting reactant : the smallest ratio (mol divide by coefficient)

P₄ : F₂ =

$\tt \dfrac{1.25}{1}\div \dfrac{6}{6}=1.25\div 1\rightarrow F_2~limiting~reactant(smallest~ratio)$

mol PF₃ based on mol of limiting reactant(F₂), so mol PF₃ :

$\tt \dfrac{4}{6}\times 6~moles=4~moles$

8 0

2 years ago

Equal volumes of H2 and o2 are placed in a balloon and then ignited. Assuming that the reaction goes to completion, which gas wi

Anastasy [175]

You will have excess O2. The ideal gas law dictates that all other variables kept the same, equal volume means equal number of moles.

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2 years ago

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The vacoule is most like a ?

Feliz [49]

Animal’s and plant cells

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2 years ago

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An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6

Eduardwww [97]

Answer : The temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

Explanation : Given,

Initial volume of gas = $261.6\times 10^{-6}m^3$

Final volume of the gas = $138.2\times 10^{-6}m^3$

Heat released = -9340 J

First we have to calculate the temperature of the gas.

According to the question, this is the case of isothermal reversible compression of gas.

As per first law of thermodynamic,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

$q=-w$

Thus, w = -q = 9340 J

The expression used for work done will be,

$w=nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = 9340 J

n = number of moles of gas = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = ?

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

$9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})$

$T=586.83K$

Now we have to calculate the final pressure of the gas by using ideal gas equation.

$PV=nRT$

where,

P = final pressure of gas = ?

V = final volume of gas = $138.2\times 10^{-6}m^3=138.2\times 10^{-9}L$

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

$P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)$

$P=1.046\times 10^{9}atm$

Therefore, the temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

6 0

2 years ago