A certain molecular compound M has a solubility in acetone of 0.737g/mL at 10.°CCalculate the mass of M that's dissolved in 9.0L of a saturated solution of M in acetone at this temperature.Be sure your answer has the correct unit symbol and number of significant digits.
1 answer:
Answer:
6633 grams of M are dissolved in 9L
Explanation:
If the compound M has a solubility in acetone of 0.737 g/mL, means that in 1 mLof solution, 0.737 grams of solute is dissolved.
Let's make a rule of three:
9 L = 9000 mL
In 1 mL ___ 0.737 g of M is dissolved
In 9000 mL ___ (9000 . 0.737) /1 = 6633 grams
You might be interested in
Answer:
Hello.
MgqI% = the formula and mass for H20 and that should be your answer for water
Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
Answer:
Chemical Reaction
Explanation:
