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stellarik [79]
3 years ago
14

In this forest, trees block much of the sunlight from reaching the ground. The branches of trees grow up and out to reach as muc

h sunlight as they can. Which challenge of life does this example represent?
Chemistry
1 answer:
lions [1.4K]3 years ago
8 0
<span>This example represents the challenge of survival of the fittest. In this situation, the trees have a distinct advantage due to their above average height. This puts them in the best position to gain the resources that they need to survive, most notably, the sun. The smaller plants, however, do not have this advantage, and lose out to the trees.</span>
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Determine the mass (in grams) of NaCl in 294 grams of a 24.1% (m/m) NaCl solution. Be sure to report to the correct number of si
IrinaVladis [17]

Answer:

70.9 grams 3 sig figs

Explanation:

24.1% of 294 grams = 0.241(294 gram) = 70.854 grams ≅ 70.9 grams 3 sig figs

8 0
3 years ago
How many moles of silver chloride are produced from 15.0 moles of silver nitrate
Ghella [55]
15.0 moles of silver chloride are produced.
7 0
3 years ago
Carbon-14 has a half-life of 5720 years and this is a first order reaction. If a piece of wood has converted 75% of the carbon-1
liraira [26]

Answer: 1145.8 years

Explanation:

Half-life of carbon-14 = 5720 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{5720\text{years}}

k=1.21\times 10^{-4}\text{years}^{-1}

Now we have to calculate the age of the sample:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{years}^{-1}

t = age of sample  = ?

a = let initial amount of the reactant  = 100 g

x = amount decayed = 75 g

a - x = amount left after decay process  = 100 - 75 = 25g

Now put all the given values in above equation, we get

t==\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{25}

t=1145.8years

8 0
3 years ago
Read 2 more answers
Oxidation number of Al(OH)4
Kobotan [32]

Explanation:

The sum of all oxidation numbers in a neutral compound is zero. The sum of all oxidation numbers in a polyatomic (many-atom) ion is equal to the charge on the ion. The oxidation number of oxygen in a compound is usually –2. The oxidation state of hydrogen in a compound is usually +1.

The oxidation state of Al in Al(OH)

4

−

x+4(+1−2)=−1

∴x=+3

The oxidation state of Mn in MnO

2

y+2(−2)=0

∴y=+4

thank u

8 0
3 years ago
What is the difference between an enzyme and a catalyst?
stealth61 [152]
Catalyst- chemical that increases the rate of a chemical reaction without itself being changed from the reaction. Enzyme- substance produced by a living organism that acts as a catalyst to bring about a particular biochemical reaction. Hope it helps.
6 0
3 years ago
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