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stellarik [79]
3 years ago
14

In this forest, trees block much of the sunlight from reaching the ground. The branches of trees grow up and out to reach as muc

h sunlight as they can. Which challenge of life does this example represent?
Chemistry
1 answer:
lions [1.4K]3 years ago
8 0
<span>This example represents the challenge of survival of the fittest. In this situation, the trees have a distinct advantage due to their above average height. This puts them in the best position to gain the resources that they need to survive, most notably, the sun. The smaller plants, however, do not have this advantage, and lose out to the trees.</span>
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PLease help!!! Im in the process of taking my final!!!!! HELPPPPP
Katarina [22]

Answer:

The answer to your question is Aluminum

Explanation:

Number of clues

1.- If this element has 3 rings in its Bohr model, we are looking for and element located in the third period of the periodic table.

For example Sodium, Magnesium, Aluminum, Silicate, Phosphorus, Sulfur, Chlorine and, Argon.

2.- It makes three bonds to become stable, then we are looking for and element located in the third group like

 Boron, Aluminum,  Gallium, Indium, etc

Conclusion

The element that has both characteristics is Aluminum

8 0
3 years ago
What further observation led mendeleev to create the periodic table
VLD [36.1K]

Answer:

;,knbbbknnbkhbln bhbj k; b; m j

Explanation:

5 0
2 years ago
According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. A 150-lb
julsineya [31]

Answer:

The density of the swimmer is 0.0342 lbm/in3.

This value makes sense as the density of the body is very similar to the water.

Explanation:

If the swimmers is floating, the weight of the swimmer must be equal to the upward buoyant force.

We can express the weight force as the product of density and volume of the swimmer.

Then

\rho_{swimmer}*V_{swimmer}=\rho_{water}*V_{water_displaced}\\\\\rho_{swimmer}*V_{swimmer}=\rho_{water}*0.95**V_{swimmer}\\\\\rho_{swimmer}=0.95*\rho_{water}\\\\\rho_{swimmer}=0.95*0.036 lbm/in3\\\\\rho_{swimmer}=0.0342lbm/in3

It makes sense as the density of the body is very similar to the water.

5 0
3 years ago
How much heat energy is required to convert 48.3 g of solid ethanol at -114.5 degree C to gasesous ethanol at 135.3 degree C? Th
OLEGan [10]

Answer:

7.21 × 10⁴ J

Explanation:

Ethanol is solid below -114.5°c, liquid between -114.5°C and 78.4°C, and gaseous above 78.4°C.

<em>How much heat energy is required to convert 48.3 g of solid ethanol at -114.5°C to gaseous ethanol at 135.3 °C?</em>

<em />

We need to calculate the heat required in different stages and then add them.

The moles of ethanol are:

48.3g.\frac{1mol}{46.07g} =1.05mol

Solid-liquid transition

Q₁ = ΔHfus . n = (4.60 kJ/mol) . 1.05 mol = 4.83 kJ = 4.83 × 10³ J

where,

ΔHfus: molar heat of fusion

n: moles

Liquid: from -114.5°C to 78.4°C

Q₂ = c(l) . m . ΔT = (2.45 J/g.°C) . 48.3g . [78.4°C-(-114.5°C)] = 2.28 × 10⁴ J

where,

c(l): specific heat capacity of the liquid

ΔT: change in the temperature

Liquid-gas transition

Q₃ = ΔHvap . n = (38.56 kJ/mol) . 1.05 mol = 40.5 kJ = 40.5 × 10³ J

where,

ΔHvap: molar heat of vaporization

Gas: from 78.4°C to 135.3°C

Q₄ = c(g) . m . ΔT = (1.43 J/g.°C) . 48.3g . (135.3°C-78.4°C) = 3.93 × 10³ J

where

c(g): specific heat capacity of the gas

Total heat required

Q₁ + Q₂ + Q₃ + Q₄ = 4.83 × 10³ J + 2.28 × 10⁴ J + 40.5 × 10³ J + 3.93 × 10³ J = 7.21 × 10⁴ J

3 0
3 years ago
A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
DaniilM [7]
800 joules because it's twice the amount
7 0
3 years ago
Read 2 more answers
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