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Anarel [89]
3 years ago
9

Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 185 L tan

ks. The liquid vaporizes quickly to gaseous nitrogen (which has a density of 1.15 g/mL at room temperature and atmospheric pressure) when the liquid is removed from the tank. Suppose that all 185 L of liquid nitrogen in a tank accidentally vaporized in a lab that measured 10.00 m times 10.00 m times 3.50 m.
Part A
What maximum fraction of the air in the room could be displaced by the gaseous nitrogen?
Chemistry
1 answer:
Serga [27]3 years ago
5 0

Answer:

37.14 %

Explanation:

Using the equation, mass, M = D1 * V1

= D2 * V2

Where,

D1 = density of the liquid Nitrogen

D2 = density of gaseous Nitrogen

V1 = volume of the liquid Nitrogen

V2 = volume of the gaseous Nitrogen

Calculating V2,

0.808 * 185 = 1.15 * V2

Volume of Nitrogen after expansion = 129.98 m3.

Volume = L * b * h

= 10 * 10 * 3.5

Volume of the room = 350 m3.

Fraction of air = volume of Nitrogen after expansion/volume of the room * 100

= 129.98/350 *100

= 37.14 %

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Explanation:

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3 years ago
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3 years ago
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Based on this, __electrons__________________ have almost no mass compared to the other particles.
Setler79 [48]

Based on this, Individual electrons in graphene have almost no mass compared to the other particles.

The material graphene consists of a single layer of carbon atoms arranged in a hexagonal lattice.

Electrons flowing through graphene can be scattered from impurities (such as foreign atoms in the lattice), from other electrons and from lattice vibrations known as phonons.

What happens to the electrons in graphene?

According to the researchers, such high values are a result of the photo thermoelectric effect. “It turns out that when you shine a light on graphene, the electrons in the material heat up, and remain hot, while the underlying carbon lattice remains cool,”

Why are electrons massless in graphene?

Yes, low energy electrons and holes in graphene can be thought of as massless because of the linear dispersion of the band structure near the K points.

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7 0
2 years ago
Using this equation 2H2+O2–&gt;2H2O when 47g of water are produced, how many grams of hydrogen must react
hoa [83]

You must react 5.3 g H_2 to produce 47 g H_2O.

<em>Step 1</em>. Calculate the <em>moles of H_2O</em>

Moles of H_2O = 47 g H_2O × (1 mol H_2O/18.02 g H_2O) =2.61 mol H_2O

<em>Step 2</em>. Calculate the <em>moles of H_2 </em>

Moles of H_2 = 2.61 mol H_2O × (2mol H_2/2 mol H_2O) = 2.61 mol H_2

<em>Step 3</em>. Calculate the <em>mass of H_2</em>

Mass of H_2 = 2.61 mol H_2 × (2.016 g H_2/1 mol H_2) = 5.3 g H_2

6 0
3 years ago
Calculate the molar mass for Cr2(SO3)3. Be sure to include units.<br><br> Number: <br><br> Units:
Vlad1618 [11]

Answer:

344.21 g/mol

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table

Explanation:

<u>Step 1: Define</u>

Cr₂(SO₃)₃

<u>Step 2: Identify</u>

Molar Mass of Cr - 52.00 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

<u>Step 3: Find</u>

Molar Mass of Cr₂(SO₃)₃ - 2(52.00) + 3(32.07) + 9(16.00) = 344.21 g/mol

3 0
3 years ago
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