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ra1l [238]
2 years ago
6

Hello, I need this question for today but I dont get it.. Can someone please help me?​

Mathematics
1 answer:
Bas_tet [7]2 years ago
3 0

Answer:

<em>A = 32²cm</em>

Hope this helped!

Step-by-step explanation:

<h3>A = lw/2</h3>

<u>We know that the width is 8cm, and that the length of the rectangle and triangle combined is 14cm.</u>

<u />

How we find the length of the triangle itself is 14cm - 6cm, since 6cm is the rectangles length (which we know because it gives it to us at the top!)

14cm - 6cm = 8cm

<h3>Now we can plug into our formula and solve</h3>

A = 8(8)/2

A = 64/2

<h3><em>A = 32²cm</em></h3>
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What expression shows a way to find 20% of 950?
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Answer:

The value of the expression is 190

Step-by-step explanation:

Given expression as :

20 % of 950

Or, \frac{20}{100} times 950

Or,  \frac{20}{100} × 950

Or, 20 × \frac{950}{100}

or, 20 × 9.5

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Ms Lim bought x pencils and two more pens than pencils. (b) Each pencil costs 60 cents and each pen costs $2. Write down, in ter
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Answer:

0.60x + ((x+2)(2)) = total cost

Step-by-step explanation:

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HELP PLEASE SIMPLIFY !!!
Lelechka [254]

Answer:

=x^{\frac{5}{6}}+2x^{\frac{7}{3}}

Step-by-step explanation:

x^{\frac{1}{3}}\left(x^{\frac{1}{2}}+2x^2\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=x^{\frac{1}{3}},\:b=x^{\frac{1}{2}},\:c=2x^2\\=x^{\frac{1}{3}}x^{\frac{1}{2}}+x^{\frac{1}{3}}\cdot \:2x^2\\=x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}\\\mathrm{Simplify}\:x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}:\quad x^{\frac{5}{6}}+2x^{\frac{7}{3}}\\x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}\\x^{\frac{1}{3}}x^{\frac{1}{2}}=x^{\frac{5}{6}}

x^{\frac{1}{3}}x^{\frac{1}{2}}\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}\\x^{\frac{1}{3}}x^{\frac{1}{2}}=\:x^{\frac{1}{3}+\frac{1}{2}}\\=x^{\frac{1}{3}+\frac{1}{2}}\\\mathrm{Join}\:\frac{1}{3}+\frac{1}{2}:\quad \frac{5}{6}\\\frac{1}{3}+\frac{1}{2}\\\mathrm{Least\:Common\:Multiplier\:of\:}3,\:2:\quad 6\\Adjust\:Fractions\:based\:on\:the\:LCM\\=\frac{2}{6}+\frac{3}{6}

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7 0
3 years ago
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