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hram777 [196]
3 years ago
12

Can someone please help me out with these 2 problem thanks

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0
3 \sqrt{-8}  + 4 \sqrt{-50}
= 3i \sqrt{8}  + 4i \sqrt{50}
= 3i \sqrt{4 \times 2}  + 4i \sqrt{25 \times 2}
= 6i \sqrt{2}  + 20i \sqrt{2}
= 26i \sqrt{2}

I think part of the second question is cut off so I can't help but I hope I have helped with the first one.
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8 + 12 = 2x<br><br> HELPPPP GOOD ANSWERS
Gennadij [26K]

Answer:

x = 10

Step-by-step explanation:

8 + 12 = 2x

8 + 12 = 20

20 = 2x

----   -----

2      2

10 = x

x = 10

5 0
3 years ago
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Let X represent the time it takes from when someone enters the line for a roller coaster until they exit on the other side. Cons
Yuri [45]

Answer:

a. E(x) = 3.730

b. c = 3.8475

c. 0.4308

Step-by-step explanation:

a.

Given

0 x < 3

F(x) = (x-3)/1.13, 3 < x < 4.13

1 x > 4.13

Calculating E(x)

First, we'll calculate the pdf, f(x).

f(x) is the derivative of F(x)

So, if F(x) = (x-3)/1.13

f(x) = F'(x) = 1/1.13, 3 < x < 4.13

E(x) is the integral of xf(x)

xf(x) = x * 1/1.3 = x/1.3

Integrating x/1.3

E(x) = x²/(2*1.13)

E(x) = x²/2.26 , 3 < x < 4.13

E(x) = (4.13²-3²)/2.16

E(x) = 3.730046296296296

E(x) = 3.730 (approximated)

b.

What is the value c such that P(X < c) = 0.75

First, we'll solve F(c)

F(c) = P(x<c)

F(c) = (c-3)/1.13= 0.75

c - 3 = 1.13 * 0.75

c - 3 = 0.8475

c = 3 + 0.8475

c = 3.8475

c.

What is the probability that X falls within 0.28 minutes of its mean?

Here we'll solve for

P(3.73 - 0.28 < X < 3.73 + 0.28)

= F(3.73 + 0.28) - F(3.73 + 0.28)

= 2*0.28/1.3 = 0.430769

= 0.4308 -- Approximated

5 0
3 years ago
I don’t understand Please help!
AlekseyPX

Answer:

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