Can someone please help me out with these 2 problem thanks

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

3 0

$3 \sqrt{-8} + 4 \sqrt{-50}$
$= 3i \sqrt{8} + 4i \sqrt{50}$
$= 3i \sqrt{4 \times 2} + 4i \sqrt{25 \times 2}$
$= 6i \sqrt{2} + 20i \sqrt{2}$
$= 26i \sqrt{2}$

I think part of the second question is cut off so I can't help but I hope I have helped with the first one.

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Un11Mid

zaharov [31]

Hello!

You draw a table or write this out

If you pick vanilla you can get 4 different fruits

That is 4 different yogurts

If you pick chocolate you can choose 4 different fruits

Same for strawberry

So there are 12 different combinations

The answer is 12

Hope this helps!

5 0

3 years ago

What is the final product? ^5sqrt4x^2 ^5sqrt4x^2

AnnyKZ [126]

For this case we have the following expression:
^ 5sqrt4x ^ 2 ^ 5sqrt4x ^ 2
Rewriting the expression we have:
((4x ^ 2) ^ (1/5)) ((4x ^ 2) ^ (1/5))
For power properties we have:
(4x ^ 2) ^ (1/5 + 1/5)
(4x ^ 2) ^ (2/5)
Rewriting we have:
(16x ^ 4) ^ (1/5)
^ 5sqrt16x ^ 4
Answer:
^5sqrt16x^4

4 0

3 years ago

The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day

Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(between 236 and 281 days)

$P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%$

b) a) P(last between 236 and 296)

$P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%$