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kvv77 [185]
2 years ago
15

(pls help my teacher wants me to pass this!) which is the graph of this line segment after it is translated - 5 units along the

x-axis and 3 units along the y-axis? (answer choices in picture)

Mathematics
2 answers:
krok68 [10]2 years ago
7 0

Answer: C

Step-by-step explanation:

Kryger [21]2 years ago
5 0

Answer:

3-th picture

Step-by-step explanation:

i think 3-th picture)

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What are the solutions to the equation -5x2 + 3x = -9
Aleks04 [339]

Answer: Move terms to the left side−52+3=−9−5x2+3x=−9−52+3−(−9)=0−


Common factor−52+3+9=0−5x2+3x+9=0−(52−3−9)=0


Divide both sides by the same factor−(52−3−9)=0−(5x2−3x−9)=052−3−9=0


Solution=3±321 over 10

Step-by-step explanation:

7 0
2 years ago
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What is the slope of the line graphed on the coordinate plane
Mice21 [21]

Answer:

The slope = 3/4

Step-by-step explanation:

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

m=\frac{6-3}{2-(-2)}=\frac{6-3}{2+2}

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5 0
2 years ago
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Write the equation of the line that passes through (-1,2) and (2,8) in any form NEED HELLP ASAP!!!
Tems11 [23]

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4 0
3 years ago
How to solve this problem im not getting a good answer
kow [346]
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7 0
3 years ago
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Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

5 0
3 years ago
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