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Helga [31]
2 years ago
6

How do I solve and find x?

Mathematics
1 answer:
oee [108]2 years ago
5 0

Answer:

x=60

Step-by-step explanation:

First get x all alone on 1 side of the equation. Add 14.5 to both sides of the equation to cancel out the negative. You will then be left with

x/5= 12

Multiply both sides of the equation by 5 to cancel out the division and you'll get x=60

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Plz solve if you can. Show ur work. I will name Brainliest! (: I need help plzzzzzzzzzz, especially on the check your work part.
maksim [4K]

1) -x + 4 = -2x - 6

Add(2x)

x+4=-6

Subtract(4)

x = -10

<u>Check your work</u>

-(-10)+4=-2(-10) - 6

10+4=-2(-10) - 6

14=-2(-10)

14=20 - 6

14=14

Correct :)

2) 4R - 4 = 3R + 10

Add 4

4R=3R+14

Subtract 3R

R = 14

<u>Check your work</u>

4(14)-4=3(14)+10

56-4=3(14)+10

52=3(14)+10

52=42+10

52=52

Correct :)

3) 2Y - 3 = Y - 4

Add 3

2Y = Y - 1

Subtract Y

Y = -1

<u>Check your work</u>

2(-1)-3=-1-4

-2-3=-1-4

-5=-5

Correct :)

<em>Hope it helps <3</em>

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A quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root. Write the equation in general form
andrey2020 [161]
<span>The general form of quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root
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It is also written as:
=> ax^2 + bx + c = 0

Quadratic equation involves unknown numbers which is x, the numbers which a, b and c are called coeffecients.
There are also quadratic factorization where you factor the polynomial give to be able to get the value of the equation.</span>



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