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Anna [14]
2 years ago
8

Each of these labelled bags contains two apples.

Mathematics
1 answer:
tamaranim1 [39]2 years ago
4 0

Answer:

bag 3

Step-by-step explanation:

Let's call the labels "green", "red", and "mix".

Pick mix for two reasons :

  1. First, it's not mixed so whatever color you pick is the color of the pair.
  2. Also, if you pick from either of the other two, you can't know if it's a mixed bag or not.

So, let's pretend you pick a red out. Move the label red to the bag. This must be true - cannot be a mix.

Now, you have the mix label <u>in your hand</u>, <u>one bag with a label</u> (green), and <u>one bag without a label</u> (previously red).

Since all bags mislabeled to begin, move the green label to the <u>blank bag</u> - since this label must be wrong.

Put the mix label on the <u>remaining bag</u>.

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Answer:

c) The total price for the service  when Terrance's price was equivalent to Sylvester's price  is $600.

Step-by-step explanation:

   Here,   t = 320.00 + 0.40 b

and  t = The total prices charged by Terrance for packing and moving b boxes.

s = 250.00 +0.50 b

and  s = The total prices charged by Sylvester  for packing and moving b boxes.

Now, to find the number of boxes, when both the prices are equal.

⇒320.00 + 0.40 b  = 250.00 +0.50 b

or, 320 - 250 = 0.50 b - 0.40 b

or, 0.10 b =  70

or, b= 70/0.10 = 700

Hence, for packing and moving b = 700 boxes, both companies charge the same amount.

Now, the price charged = 320 + 0.4 (b)

                                         = 320 + 0.4(70) = 320 + 280

                                         = 600

or,  the total price for the service  when Terrance's price was equivalent to Sylvester's price  is $600.

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The answer is permutation !
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