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kodGreya [7K]
3 years ago
5

A 2kg object travels to the right at 5.5 m/s after colliding with a 3kg object, initially at rest, what are the speeds of each o

bject after the collision l?

Physics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

Velocity of Object with 2 kg= 3.390 m/s

Velocity of Object with 3 kg= 3.404 m/s

Explanation:

From the picture, it can be seen that object B is initially at rest while object A is travelling at a speed of 5m/s. After the collision, Object A moves at an angle of 65 degrees while object B moves at an angle of 37 degrees.

We also know that momentum of a closed system is conserved.

Initial momentum along the x-axis = 2*5.5 = 11

Initial momentum along y-axis = 0

Final momentum along x-axis= a*Cos(65)*2 +b*Cos(37) *3= 11 (a is the velocity of object A of 2 kg after collision where as b is the velocity of object B of 3 kg after collision. velocity is multiplied by cosines of the angle from x axis to give the horizontal component of the velocities).

Final momentum along y-axis = a*Sin(65)*2 - b*Sin(37)*3 =0 (We can see that vertical components of velocity are opposite in direction to each other)

Solve both the equations simultaneously for a and b.

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The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.

Explanation:

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8 0
3 years ago
Several light bulbs, each of resistance 1.5 Ω, are connected in a series across a 120 V source of emf. If the current through th
Leni [432]
<h3><u>Answer;</u></h3>

40 light bulbs

<h3><u>Explanation</u>;</h3>

The total resistance of components or bulbs in series is given as the sum of resistance of all the components.

Thus; if there are bulbs in series each with a resistance of 1.5 Ω, the the total resistance will be; 1.5nΩ

From the ohms law;

V = IR , where V is the voltage, I is the current and R is the resistor.

Thus; R = V/i

         R = 120/2

            = 60 Ω

But, there are n bulbs each with 1.5 Ω; thus there are;

n = 60/1.5

<u>  = 40 Bulbs </u>

7 0
3 years ago
Friction force affects the work done by the applied force.<br><br>T OR F ​
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Answer:

TRUE.

Explanation:

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When a constant force acts upon an object, the acceleration of the object varies inversely with its mass 2kg. When a certain con
BARSIC [14]

Answer:

The acceleration of the second object is 4 m/s².

Explanation:

Given that,

when the a constant force acts upon an object, the acceleration varies inversely with its mass .

mass\propto \frac{1}{acceleration}

We can rewrite the equation as

\frac{m_1}{m_2}=\frac{a_2}{a_1}

When an a certain constant force acts upon an object with mass 2 kg , the acceleration of the object is 26 m/s².

Here, m_1 = 2 kg, a_1 = 26 m/s²,m_2 = 13 kg and a_2=?

\frac{m_1}{m_2}=\frac{a_2}{a_1}

\frac{2}{13}=\frac{a_2}{26}

\Rightarrow \frac{a_2}{26}= \frac{2}{13}

\Rightarrow {a_2}= \frac{2}{13}\times 26

\Rightarrow a_2=4 m/s²

The acceleration of the second object is 4 m/s².

3 0
3 years ago
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