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posledela
3 years ago
8

A pendulum that moves through its equilibrium position once every 1.000 s is sometimes called a "seconds pendulum."

Physics
1 answer:
garik1379 [7]3 years ago
3 0
 <span>I would solve this problem by starting from the equation for a pendulum's period: 

T ≈ 2π√( L / g ) 

Rearranging for g, and substituting the length in Cambridge: 

g ≈ ( 4π² * L ) / T² 
. . = ( 4π * 0.9942 m ) / ( 1.000 s + 1.000 s )² 
. . = 9.812 m/s² 

And for Tokyo: 

g ≈ ( 4π² * L ) / T² 
. . = ( 4π * 0.9927 m ) / ( 1.000 s + 1.000 s )² 
. . = 9.798 m/s²</span>
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Answer:

4.32

Explanation:

The centripetal acceleration of any object is given as

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v = the linear acceleration

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Since we are not given directly the centripetal acceleration, we'd be using the value of acceleration due to gravity, 9.8. This means that

9.8 = v²/1.9

v² = 1.9 * 9.8

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v = 4.32 m/s

This means that, the minimum speed the cup must have so as not to get wet or any spill is 4.32 m/s

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3 years ago
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Answer:

17.7 m/s

Explanation:

Given:

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The ball is moving at a speed of 17.7 m/s when it hits the ground.

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algol13
<span>In Thomson experiment, why was the glowing beam repelled by a negatively charged plate, because the glowing beam was negatively charged. The glowing beam particles were attracted to the positive plate.

</span><span>J.JThomson proved that the cathode rays produced a stream of negatively charged particles called electrons. </span>
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