Answer:
14.0351 years
Explanation:
80km / 5.7km per year = 14.0351 years
Answer:
Orbital period, T = 1.00074 years
Explanation:
It is given that,
Orbital radius of a solar system planet,
The orbital period of the planet can be calculated using third law of Kepler's. It is as follows :
M is the mass of the sun
T = 31559467.6761 s
T = 1.00074 years
So, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about 1.00074 years.
it's just 1/8, no pi included (if you're on APEX)
Answer:
Explanation:
We have:
diameter of the wheel,
weight of the wheel,
mass of hanging object to the wheel,
speed of the hanging mass after the descend,
height of descend,
(a)
moment of inertia of wheel about its central axis:
Answer:
B = 5.59x10⁹ T
Explanation:
The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:
<u>We have:</u>
F = 1.4x10⁻³ N
v = 2.6x10⁶ m/s
θ = 37.0°
q = 2*p = 2*1.6x10⁻¹⁹ C
Hence, the strength of the magnetic field is:
Therefore, the strength of the magnetic field is 5.59x10⁹ T.
I hope it helps you!