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3 years ago

A pendulum completes 2 oscillation in 5s.

Physics

1 answer:

Otrada [13]3 years ago

6 0

Answer:

Explanation:

<h3>Given :-</h3><h2>Completes 2 oscillation in 5s.</h2><h2>A) Time period = ?</h2><h2 /><h2> $t \: = \frac{total \: time \: }{total \: no \: of \: oscillation}$ </h2><h2 /><h2> $\frac{5}{2} = 2.5s$ </h2>

<em>Thus 1 oscillation is completed in 2.5 </em><em>s.</em>

<h2>B) If g = 9.8 ms−², find its length.</h2><h2> $t \: = 2\pi \frac{ \sqrt{l} }{g }$ </h2><h3>= 2.5s </h3><h3> $2\pi \frac{ \sqrt{l} }{g}$ </h3><h3>Length = ? </h3><h2> $\frac{ {t}^{2} }{4\pi {}^{2} } \times g$ </h2><h3 /><h3> $\frac{2.5}{ {4}^{2} } \times 9.8 = 1.55m$ </h3>

Thus the length of g = 9.8 ms −² = 1.55m

<h2>Hope it helps u.......</h2><h2>STAY SAFE, STAY HEALTHY AND BLESSED .</h2><h2> HAVE A MARVELOUS DAY AHEAD !</h2><h2>THANK YOU !</h2>

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The spring mass system creates a harmonic oscillator that is described by the equation

x = Acos (wt + φ)

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a) Let's reduce the SI system

x = 17.0 cm (1 m / 100 cm) = 0.170 m

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w = √ (k / m)

w = √ 11 / 0.200

w = 7.416 rad / s

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0.170 = A cos φ

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v = dx / dt

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Let's write the two equations

0.170 = A cos φ

2.0 / 7.416 = -A sin φ

Let's divide those equations

tan φ= 2.0 / (7.416 0.170)

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φ= 1.008 rad

We calculate A

A = 0.170 / cos φ

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A = 0.3187 m

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b) the speed can be found by derivatives

v = dx / dt

v = - 0.3187 7.416 sin (7.416 t +1.008)

v = -2,363 sin (7,416 t + 1,008)

c) the acceleration we look for conserved

a = dv / dt

a = -2,363 7,416 cos (7,416 t + 1,008)

a = - 17.52 cos (7.416t + 1.008)

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