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3 years ago

A pendulum completes 2 oscillation in 5s.

Physics

1 answer:

Otrada [13]3 years ago

6 0

Answer:

Explanation:

<h3>Given :-</h3><h2>Completes 2 oscillation in 5s.</h2><h2>A) Time period = ?</h2><h2 /><h2> $t \: = \frac{total \: time \: }{total \: no \: of \: oscillation}$ </h2><h2 /><h2> $\frac{5}{2} = 2.5s$ </h2>

<em>Thus 1 oscillation is completed in 2.5 </em><em>s.</em>

<h2>B) If g = 9.8 ms−², find its length.</h2><h2> $t \: = 2\pi \frac{ \sqrt{l} }{g }$ </h2><h3>= 2.5s </h3><h3> $2\pi \frac{ \sqrt{l} }{g}$ </h3><h3>Length = ? </h3><h2> $\frac{ {t}^{2} }{4\pi {}^{2} } \times g$ </h2><h3 /><h3> $\frac{2.5}{ {4}^{2} } \times 9.8 = 1.55m$ </h3>

Thus the length of g = 9.8 ms −² = 1.55m

<h2>Hope it helps u.......</h2><h2>STAY SAFE, STAY HEALTHY AND BLESSED .</h2><h2> HAVE A MARVELOUS DAY AHEAD !</h2><h2>THANK YOU !</h2>

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Keith_Richards [23]

<h2>Answer: Toward the center of the circle.</h2>

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miskamm [114]

Answer:

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Explanation:

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An object has the acceleration graph shown in (Figure 1). Its velocity at t=0s is vx=2.0m/s. Draw the object's velocity graph fo

timama [110]

Answer:

Explanation:

We may notice that change in velocity can be obtained by calculating areas between acceleration lines and horizontal axis ("Time"). Mathematically, we know that:

$v_{b}-v_{a} = \int\limits^{t_{b}}_{t_{a}} {a(t)} \, dt$

$v_{b} = v_{a}+ \int\limits^{t_{b}}_{t_{a}} {a(t)} \, dt$

Where:

$v_{a}$ , $v_{b}$ - Initial and final velocities, measured in meters per second.

$t_{a}$ , $t_{b}$ - Initial and final times, measured in seconds.

$a(t)$ - Acceleration, measured in meters per square second.

Acceleration is the slope of velocity, as we know that each line is an horizontal one, then, velocity curves are lines with slopes different of zero. There are three region where velocities should be found:

Region I (t = 0 s to t = 4 s)

$v_{4} = 2\,\frac{m}{s} +\int\limits^{4\,s}_{0\,s} {\left(-2\,\frac{m}{s^{2}} \right)} \, dt$