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erma4kov [3.2K]
3 years ago
13

Which of the following is not a primary cause of eroding rock

Physics
1 answer:
Pavel [41]3 years ago
4 0
The answer to this is Animal habitation 
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An elevator weighing 2,200 lbs is raised one story in 20 seconds. If the distance between stories is 10 feet, the power is devel
kaheart [24]

Answer: 1100 ft lb/s and 2 H.P

Explanation:

To calculate for the power developed in the elevator motor in ft.lb/s, we multiply the distance and the weight of the elevator and divide the product by the time.

                      Power = (10 ft)(2200 lb) / 20 s = 1100 ft.lb/s

Next, convert the calculated value to HP. 

                             1100 ft.lb/s x (1 HP/ 550 ft.lb/s) = 2 HP

hope this helps please give brainliest!

5 0
3 years ago
Electromagnetic force is present when electromagnetic fields
AlekseyPX

b is the correct answer

4 0
3 years ago
Read 2 more answers
The force attraction between two objects, does what, as the distance between them increases?
gregori [183]

Decreases

Explanation:

The force of attraction between two objects will decrease as the distance between them increases.

This is in compliance with newtons law of universal gravitation.

The force of attraction between the two bodies is a gravitational force.

According to newton's law of universal gravitation "the force of attraction between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".

 We see that from the last statement, the force of attraction between  is inversely proportional to the square of the distances between them.

          F ∞ \frac{1}{r^{2} }

r is the distance between them.

learn more:

Universal gravitation brainly.com/question/1724648

#learnwithBrainly

3 0
3 years ago
A spring with spring constant of 33 N/m is stretched 0.15 m from its equilibrium position. How much work must be done to stretch
Hoochie [10]

Work done is 0.442J

<u>Explanation:</u>

Given:

Spring constant, k = 33 N/m

Distance, x₁ = 0.15m

Additional distance, x₂ = 0.072 m

Total distance = 0.15 + 0.072 m

                        = 0.222 m

Work done, W = ?

We can calculate work done by the formula

W = \frac{1}{2}kx_2^2 - \frac{1}{2}kx_1^2

On substituting the value we get:

W = \frac{1}{2}k [(x_2)^2  - (x_1)^2]\\ \\W = \frac{1}{2} X 33[(0.222)^2 - (0.15)^2]\\ \\W = \frac{1}{2}X 33 [ 0.0493 - 0.0225]\\ \\W = 0.442 J

Therefore, work done is 0.442J

7 0
3 years ago
The weight of a boy having a mass of 50 kg is_____ N
Elden [556K]

Answer: 490

Explanation:

5 0
3 years ago
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