2 years ago

You connected the 5 Ω, 10 Ω, 15 Ω resistors in series with a 90 V battery. What is the current?

Physics

1 answer:

kykrilka [37]2 years ago

3 0

Answer:

Explanation:

Rtoal=R1+R2+R3=5+10+15=30

I=V/R 90/30

I=3

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You connected the 5 Ω, 10 Ω, 15 Ω resistors in series with a 90 V battery. What is the current?​

You connected the 5 Ω, 10 Ω, 15 Ω resistors in series with a 90 V battery. What is the current?