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3 years ago

What particle collides with a fissionable nucleus in order to begin the fission process?

Physics

1 answer:

adoni [48]3 years ago

3 0

Answer:

neutrons

Explanation:

Neutrons are usually released when fission takes place. Fission of a nucleus may be spontaneous, that is, it may happen at random due to internal processes within the nucleus. Fission can also be induced by bombarding a nucleus with a neutron.

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I need help pls help

Nikitich [7]

You want all those boxes filled in (0,0)

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4 years ago

Gabriella got a burn on her arm from a chemical spill and rinsed the area thoroughly with water. Which piece of safety equipment

ioda

I believe it she should use the first aid kit next

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3 years ago

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The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of t

Sphinxa [80]

Answer:

The power consumed by the air filter is 9.936 watts

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, $\dfrac{N_s}{N_p}=\dfrac{46}{1}$

Voltage of primary coil, $V_p=120\ V$

Current in the secondary coil, $I_s=1.8\times 10^{-3}\ A$

The power consumed by the air filter is :

$P_s=I_s\times V_s$ ...........(1)

For a transformer, $\dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}$

So, $P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p$

$P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120$

$P_s=9.936\ Watts$

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.

3 0

4 years ago

Read 2 more answers

You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 12-m-hi

Vlada [557]

Answer:

Vmax=11.53 m/s

Explanation:

from conservation of energy

$E_A} =E_{B}$

Spring potential energy =potential energy due to elevation

0.5*k*x²= mg $(h_{B}-h_{A} )$ =mgh

0.5*k*2.3²= 430*9.81*6

k=9568.92 N/m

For safety reason

k"=1.13 *k= 1.13*9568.92

k"=10812.88 N/m

agsin from conservation of energy

$E_A} =E_{C}$

spring potential energy=change in kinetic energy

0.5*k"*x²=0.5*m* $V_{max}^{2}$

10812.88 *2.3²=430* $V_{max}^{2}$

$V_{max}$ =11.53 m/s

5 0

4 years ago

488 nm light passes through a single

swat32

Answer:

5.00

Explanation:

a sinθ=mλ

You are missing (a) so you move sinθ to the other side than solve from there.

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3 years ago