Answer:
2280 V
Explanation:
distance between the plates, d = 4 cm = 0.04 m
Electric field strength, E = 5.7 x 10^4 V/m
The formula for potential difference is given by
V = E x d
V = 5.7 x 10^4 x 0.04
V = 2280 V
thus, the potential difference between the plates is 2280 V.
Answer:
- Here we use the conservation of momentum theorem.
- m stands for mass, and v stands for velocity. The numbers refer to the respective objects.
- m1v1 + m2v2 = m1vf1 + m2vf2
- Since the equation is perfectly inelastic, the final velocity of both masses is the same. Let’s account for this in our formula.
- m1v1 + m2v2 = vf(m1 + m2)
<u>Let’s substitute in our givens.</u>
(0.002 kg)(700 m/s) + (5 kg)(0 m/s) = vf(0.002 kg + 5 kg)
I assume you are proficient in algebra I, so I will not include the steps to simplify this equation.
Note that I have considered the bullet’s velocity to be in the positive direction,
The answer is vf = 0.280 m/s
Answer:
1.52s
Explanation:
Given parameters:
Acceleration = 63m/s²
Final velocity = 96m/s
Unknown:
Time taken = ?
Solution:
To solve this problem, we use one of the kinematics equation:
v = u + at
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
So;
96 = 0 + 63t
t = 1.52s
