Plastic is what they are made of
This question can have ALOT of answers but ill leave you with these summed up points and you can take what you need from it they are get right to the point! Sorry if they long paragraphs scare you lol
*You want to provide patients the best care possible. Most often your patients will have a disease. Diseases result when there is something abnormal in the anatomy and physiology of a structure. With a car, you can’t understand how to fix an engine if you don’t know how it works. The same is true with your patients. You can’t really understand how to treat them or why the treatment works, if you don’t understand how the effected body system normally functions.
*Patients will want to understand their diseases. In order to help them understand what is going wrong, you have to first understand how a particular organ is supposed to work. In addition, you will need to be able to explain these things to patients in a way that they can understand. If you don’t understand it well, you won’t be able to explain it. Your patient’s confidence in your ability will be at least partially determined by your ability to discuss what you are doing and why you are doing it. You will need to look up information if you are not sure.
*Organ systems are so interconnected that a disease in one system may result in a symptom in another system. Without seeing the normal interconnectedness, you cannot fully understand the disease.
*Success in an allied health field requires at least three things. First, you must have the personality to be able to support and help patients. Secondly, you must have the scientific and technical knowledge necessary to make the correct decisions regarding patient care. Thirdly, you must have the clinical skills necessary to implement this kno
Answer:
a) 4.49Hz
b) 0.536kg
c) 2.57s
Explanation:
This problem can be solved by using the equation for he position and velocity of an object in a mass-string system:
![x=Acos(\omega t)\\\\v=-\omega Asin(\omega t)\\\\a=-\omega^2Acos(\omega t)](https://tex.z-dn.net/?f=x%3DAcos%28%5Comega%20t%29%5C%5C%5C%5Cv%3D-%5Comega%20Asin%28%5Comega%20t%29%5C%5C%5C%5Ca%3D-%5Comega%5E2Acos%28%5Comega%20t%29)
for some time t you have:
x=0.134m
v=-12.1m/s
a=-107m/s^2
If you divide the first equation and the third equation, you can calculate w:
![\frac{x}{a}=\frac{Acos(\omega t)}{-\omega^2 Acos(\omega t)}\\\\\omega=\sqrt{-\frac{a}{x}}=\sqrt{-\frac{-107m/s^2}{0.134m}}=28.25\frac{rad}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Ba%7D%3D%5Cfrac%7BAcos%28%5Comega%20t%29%7D%7B-%5Comega%5E2%20Acos%28%5Comega%20t%29%7D%5C%5C%5C%5C%5Comega%3D%5Csqrt%7B-%5Cfrac%7Ba%7D%7Bx%7D%7D%3D%5Csqrt%7B-%5Cfrac%7B-107m%2Fs%5E2%7D%7B0.134m%7D%7D%3D28.25%5Cfrac%7Brad%7D%7Bs%7D)
with this value you can compute the frequency:
a)
![f=\frac{\omega}{2\pi}=\frac{28.25rad/s}{2\pi}=4.49Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B%5Comega%7D%7B2%5Cpi%7D%3D%5Cfrac%7B28.25rad%2Fs%7D%7B2%5Cpi%7D%3D4.49Hz)
b)
the mass of the block is given by the formula:
![f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}\\\\m=\frac{k}{4\pi^2f^2}=\frac{427N/m}{(4\pi^2)(4.49Hz)^2}=0.536kg](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7B2%5Cpi%7D%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D%5C%5C%5C%5Cm%3D%5Cfrac%7Bk%7D%7B4%5Cpi%5E2f%5E2%7D%3D%5Cfrac%7B427N%2Fm%7D%7B%284%5Cpi%5E2%29%284.49Hz%29%5E2%7D%3D0.536kg)
c) to find the amplitude of the motion you need to know the time t. This can computed by dividing the equation for v with the equation for x and taking the arctan:
![\frac{v}{x}=-\omega tan(\omega t)\\\\t=\frac{1}{\omega}arctan(-\frac{v}{x\omega })=\frac{1}{28.25rad/s}arctan(-\frac{-12.1m/s}{(0.134m)(28.25rad/s)})=2.57s](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7Bx%7D%3D-%5Comega%20tan%28%5Comega%20t%29%5C%5C%5C%5Ct%3D%5Cfrac%7B1%7D%7B%5Comega%7Darctan%28-%5Cfrac%7Bv%7D%7Bx%5Comega%20%7D%29%3D%5Cfrac%7B1%7D%7B28.25rad%2Fs%7Darctan%28-%5Cfrac%7B-12.1m%2Fs%7D%7B%280.134m%29%2828.25rad%2Fs%29%7D%29%3D2.57s)
Finally, the amplitude is:
![x=Acos(\omega t)\\\\A=\frac{0.134m}{cos(28.25rad/s*2.57s )}=0.45m](https://tex.z-dn.net/?f=x%3DAcos%28%5Comega%20t%29%5C%5C%5C%5CA%3D%5Cfrac%7B0.134m%7D%7Bcos%2828.25rad%2Fs%2A2.57s%20%29%7D%3D0.45m)
Supposing the runner is condensed to a point and moves upward at 2.2 m/s.
It takes a time = 2.2/g = 2.2/9.8 = 0.22 seconds to increase to max height.
Now looking at this condition in opposite - that is the runner is at max height and drops back to earth in 0.22 s (symmetry of this kind of motion).
From what height does any object take 0.22 s to fall to earth (supposing there is no air friction)?
d = 1/2gt²= (0.5)(9.8)(0.22)²= 0.24 m