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Answer:
2x(x - 4)
Step-by-step explanation:
![2 {x}^{2} - 8x \\ \\ = 2x(x - 4)](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%20-%208x%20%5C%5C%20%20%5C%5C%20%20%3D%202x%28x%20-%204%29)
Answer:
![Length=7units\\\\Width=5units](https://tex.z-dn.net/?f=Length%3D7units%5C%5C%5C%5CWidth%3D5units)
Step-by-step explanation:
Width=(Length-2) units
W=(L-2) units
Area of the rectangle= 35 square units
Area = length* Width
![35= L*(L-2)\\\\35=L^2-2L](https://tex.z-dn.net/?f=35%3D%20L%2A%28L-2%29%5C%5C%5C%5C35%3DL%5E2-2L)
Subtracting 35 both sides:
![L^2-2L-35=0](https://tex.z-dn.net/?f=L%5E2-2L-35%3D0)
Solving the quadratic equation for 'L' ;
Using factorization:
![L^2+5L-7L-35=0](https://tex.z-dn.net/?f=L%5E2%2B5L-7L-35%3D0)
Taking common from the equation :
![L(L+5)-7(L+5)=0\\\\(L+5)(L-7)=0\\\\L+5=0\\\\L=-5](https://tex.z-dn.net/?f=L%28L%2B5%29-7%28L%2B5%29%3D0%5C%5C%5C%5C%28L%2B5%29%28L-7%29%3D0%5C%5C%5C%5CL%2B5%3D0%5C%5C%5C%5CL%3D-5)
OR
![L-7=0\\\\L=7](https://tex.z-dn.net/?f=L-7%3D0%5C%5C%5C%5CL%3D7)
The length cannot be negative, therefore Length(L)= 7
![Width=Length-2\\\\=7-2\\\\=5 units](https://tex.z-dn.net/?f=Width%3DLength-2%5C%5C%5C%5C%3D7-2%5C%5C%5C%5C%3D5%20units)
![Length=7units\\\\Width=5units](https://tex.z-dn.net/?f=Length%3D7units%5C%5C%5C%5CWidth%3D5units)
Answer:
this has happened to me before. unfortunately I had to refresh the page.
Step-by-step explanation:
write down the answers you already have done.
Answer:
1.
-2 = x/4 + 1
Subtract 1 from both sides:
-2 - 1 = x/4 + 1 - 1
-3 = x/4
Multiply both sides by 4:
-3 * 4 = x/4 * 4
-12 = x
2.
3x+5
3.
X= 12 or 18
This could be read two different ways.
0=2/3x-12
12=2/3x
12÷2/3=x
12*3/2=x
18=x
—-OR—-
0=2/3(x-12)
0=2/3x-8
8=2/3x
8÷2/3=x
8*3/2=x
12=x