Answer:
m∠BOC = 40°
Step-by-step explanation:
Given O A ‾ ⊥ O C ‾ OA ⊥ OC m∠BOC=6x−6 ∘
m∠AOB=5x+8 ∘
Find m ∠ B O C:
This means that: m∠BOC and m∠AOC intersect at a right angle.
Hence:
m∠BOC + m∠AOC = 90°
Step 1
Solving for x
6x - 6 + 5x + 8 = 90°
11x -2 = 90°
11x = 90 - 2
11x = 88
x = 88/11
x = 8
Step 2
Solving for m∠BOC
m∠BOC = 6x - 8
m∠BOC = 6(8) - 8
= 48 - 8
= 40°
Answer: y = -4/5x - 12
1. First find slope. Since you are trying to find a line perpendicular to y = 5/4x + 10, the slope would be the negative reciprocal of 5/4x.
slope = - 4/5x
2. plug in (-5,-8) and the slope of -4/5 to the point slope form equation
(y-y2) = slope (x-x2)
= y+8=-4/5(x+5)
3. solve and simply y+8=-4/5(x+5)
y = -4/5x - 12 is your answer
I hope this helps you
%50.?=30
50/100.?=30
1/2.?=30
?=30.2
?=60