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Naddik [55]
2 years ago
11

What is the difference between a solution with a ph of 2 and a solution with a ph of 10?

Chemistry
1 answer:
matrenka [14]2 years ago
4 0

Answer:

the concentration of protons

Explanation:

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Are solar and lunar eclipses processed by the movements of the Earth and moon?
Inga [223]

Explanation:

As the Earth rotates on its axis and revolves around the Sun, several different effects are produced. When the new moon comes between the Earth and the Sun along the ecliptic, a solar eclipse is produced. When the Earth comes between the full moon and the Sun along the ecliptic, a lunar eclipse occurs.

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3 years ago
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Help me plz with these problems
loris [4]
1 it a 2 it b 3 it c 4 it be 7 it a
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IF 500 mL of air contains 2.50x10^22 particles (atoms and molecules). how much particles do you inhale in one day if you breath
vaieri [72.5K]

Answer:

I think it is 0.00192

Explanation:

28.795705

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8 0
3 years ago
4. The volume of a sample of a gas at STP is 200.0 ml. If the pressure is increased to 4.00 atmospheres (temperature constant),
Elina [12.6K]

Answer : The value of new volume is, 50.0 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure at STP = 1 atm

P_2 = final pressure =  4.00  atm

V_1 = initial volume at STP = 200.0 mL

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

1atm\times 200.0mL=4.00atm\times V_2

V_2=50.0mL

Therefore, the value of new volume is, 50.0 mL

6 0
4 years ago
The gasses in a hair spray can are at temperature 300k and a pressure of 30 atm, it
Sergeeva-Olga [200]

Answer:

900 K

Explanation:

Recall the ideal gas law:

\displaystyle PV = nRT

Because only pressure and temperature is changing, we can rearrange the equation as follows:
\displaystyle \frac{P}{T} = \frac{nR}{V}

The right-hand side stays constant. Therefore:

\displaystyle \frac{P_1}{T_1} = \frac{P_2}{T_2}

The can explodes at a pressure of 90 atm. The current temperature and pressure is 300 K and 30 atm, respectively.

Substitute and solve for <em>T</em>₂:

\displaystyle \begin{aligned} \frac{(30\text{ atm})}{(300\text{ K})} & = \frac{(90\text{ atm})}{T_2} \\ \\ T_2 & = 900\text{ K}\end{aligned}

Hence, the temperature must be reach 900 K.

7 0
3 years ago
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