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svetoff [14.1K]
2 years ago
7

Predict the missing component of each reaction.

Chemistry
2 answers:
Aleks [24]2 years ago
8 0

Answer:

2Na + Cl2 → 2NaCl

2MgO → 2Mg + O2

Snowcat [4.5K]2 years ago
7 0

Answer:

2NaCl

2Mg + O2

Explanation:

hope it helps

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If you keep heating a liquid, what happens to the energy of the particles in the liquid?​
larisa86 [58]

Answer:

theres gonna be more energy and some of the particles with a lot of energy will become vapor and evaporate

Explanation:

"If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid. The most energetic particles at the surface escape from the surface of the liquid as a vapor as it gets warmer. Liquids evaporate faster as they heat up and more particles have enough energy to break away."

6 0
3 years ago
A sample of Freon-12 (CF2Cl2) occupies 2.842 x 101 L at 331 K and 2.525 x 102 kPa. Find its volume (in L) at standard temperatur
Angelina_Jolie [31]
We have to first find the number of moles of Freon-12 in the sample using the ideal gas law equation
PV = nRT
n = \frac{PV}{RT}
since the number of moles at both conditions given and at stp we can write the following formula 
\frac{P1V1}{RT1} =  \frac{P2V2}{RT2}
where parameters for the given conditions are on the left side and parameters for STP conditions are on the right side of the equation
where P1 - pressure - 252.5 kPa
V1 - volume - 28.42 x 10⁻³ m³ 
R - universal gas constant 
T1 - 331 K

STP conditions 
P2 - 101 325 Pa
T2 - 273 K

substituting these values in the equation 

\frac{252 500Pa*28.42*10 ^{-3}m^{3}  }{R*331K} =  \frac{101325 Pa*V}{R*273 K}

V = 58.41 L
Volume at STP is 58.41 L
3 0
3 years ago
At a certain temperature, the ph of a neutral solution is 7.78. what is the value of kw at that temperature? express your answer
Strike441 [17]
Given the pH of the solution, we can determine [H⁺]. 

pH = -log[H⁺]
[H⁺] = 10⁻⁷·⁷⁸
[H⁺] = 1.659586907 x 10⁻⁸ M

We also know that pOH = 14 - pH. Thus, the pOH is  6.22. Given the pOH of the solution, we can determine [OH⁻]. 

pOH = -log[OH⁻]
[OH⁻] = 10⁻6.22
[OH⁻] =  6.02559586 x 10⁻⁷ M

The ionic product of water Kw, can then be calculated using the following equation.

Kw = [H⁺][OH⁻]
Kw = (1.659586907 x 10⁻⁸)(6.02559586 x 10⁻⁷)
Kw = 1.0 x 10⁻¹⁴
8 0
4 years ago
Runoff from agricultural land carries chemicals from fertilizers that collect in a lake. The buildup of chemicals can eventually
bagirrra123 [75]

Answer:

what are the roles of minerals in maintaning homeostasis?

5 0
3 years ago
Mothballs are composed primarily of the hydrocarbon naphthalene (C10H8)(C10H8). When 1.025 gg of naphthalene is burned in a bomb
konstantin123 [22]

<u>Answer:</u> The enthalpy of the reaction is -5167.71 kJ

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 5.11 kJ/°C

\Delta T = change in temperature = T_2-T_1=(32.33-24.25)^oC=8.08^oC

Putting values in above equation, we get:

q=5.11kJ/^oC\times 8.08^oC=41.29kJ

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of naphthalene = 1.025 g

Molar mass of naphthalene = 128.2 g/mol

Putting values in above equation, we get:

\text{Moles of naphthalene}=\frac{1.025g}{128.2g/mol}=0.00799mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = -41.29 kJ

n = number of moles of naphthalene = 0.00799 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-41.29kJ}{0.00799mol}=-5167.71kJ/mol

Hence, the enthalpy of the reaction is -5167.71 kJ

3 0
3 years ago
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