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2 years ago

Which type of scientist would most likely study how electricity could be

Chemistry

1 answer:

Nikolay [14]2 years ago

6 0

Electrical engineers are the scientists that study the production of electricity more efficient.

<h3>Which type of scientist would study how electricity could be produced more efficiently?</h3>

Electrical engineers are the type of scientist that would most likely study how electricity could be produced more efficiently because they produced new technologies which are cost efficient as well as produce high amount of electricity.

So we can conclude that electrical engineers are the scientists that study the production of electricity more efficient.

Learn more about electricity here: brainly.com/question/776932

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You might be interested in

In what type of reaction or process does heat flow into the system

SCORPION-xisa [38]

Answer: The correct answer is: " endothermic . "

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Note: Heat flows into [heat may be absorbed within] an "endothermic" reaction or system

To the contrary, heat flows out  [heat may exit from or may be released from] an "exothermic" reaction or process.

Hint: Think of the "prefixes" of: "endothermic" and "exothermic" :

_____________________________________

1) endo- = "within" (as in "endothermic" —heat tends to be absorbed/"within"/"released within"/released within"/into" ;

2) exo- = " outwards"/"exit" (as in "exothermic") —heat tends to '"exit"/leave/escape from/"be released out of/form".

_____________________________________

Hope this is helpful to you!

Best wishes to you in your academic pursuits

—and within the "Brainly" community"!

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5 0

3 years ago

Nitric acid is a key industrial chemical, largely used to make fertilizers and explosives. The first step in its synthesis is th

kolbaska11 [484]

Answer: When using 645 L /s of O2 in a temperature and pressure of 195°C, 0.88 atm respectively, we will get 0.355Kg /s NO

Explanation:

First we review the equation that represents the oxidation process of the NH3 to NO.

4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)

Second we gather the information what we are going to use in our calculations.

O2 Volume Rate = 645 L /s

Pressure = 0.88 atm

Temperature = 195°C + 273 = 468K

NO molecular weight = 30.01 g/mol

Third, in order to calculate the amount of NO moles produced by 645L/ s of O2, we must find out, how many moles (n) are 645L O2 by using the general gas equation PV =n RT

Let´s keep in mind that using this equation our constant R is 0.08205Lxatm/Kxmol

PV =n RT

n= PV / RT

n= [ 0.88atm x 645L/s] / [ (0.08205 Lxatm/Kxmol) x 468K]

n= 14.781 moles /s of O2

Fourth, now by knowing the amount of moles of O2, we can use the equation to calculate how many moles of NO will be produced and then with the molecular weight, we will finally know the total mass per second .

14.781 moles /s of O2 x 4moles NO / 5 moles O2 x 30.01g NO / 1 mol NO x 1Kg NO /1000g NO = 0.355Kg /s NO

6 0

3 years ago

The motion of objects can be quite complex. The motion of this frog is an example. Suppose that the frog moves from one lily pad

olga2289 [7]

Answer:

The speed of the frog is 1m per second the velocity is he can turn and jump in a different direction in 1 second the distance is 1m and there is no displacement. I'm pretty sure this is right

Explanation:

8 0

3 years ago

3. What will you observe (the dependent variable) as a result of that change?

Novay_Z [31]

You will observe the the project that your trying to do an watch the change

8 0

4 years ago

A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant

KiRa [710]

Answer:

$V_2=2.995L\\\\W=248.5J$

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

$P_1V_1=P_2V_2$

So we solve for $V_2$ by firstly computing the initial pressure:

$P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L} =11.98atm$

$V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L$

Finally, we can compute the work by using the following formula:

$W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J$

Best regards.

4 0

3 years ago