A boy who weighs 30 kg is skateboarding at a speed of 5 m/s. What is the boys kinetic energy?

So confused can someone help ?

nika2105 [10]

Answer:

well in a solid pack together as tightly as possible in a neat and ordered arrangement.

and a liquid are close together (touching) but they are able to move/slide/flow past each other

Explanation:

6 0

3 years ago

One different between mixtures and pure substance is that

myrzilka [38]

Answer:

Pure substances cannot be separated into any other kinds of matter, while a mixture is a combination of two or more pure substances.

Explanation:

4 0

3 years ago

Read 2 more answers

The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t

const2013 [10]

Answer:

$\boxed{\text{47.4 g}}$

Explanation:

We are given the mass of two reactants, so this is a limiting reactant problem.

We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r: 17.03 32.00 18.02

4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

m/g: 70.1 70.1

Step 1. Calculate the moles of each reactant

$\text{Moles of CO } = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{17.03 g}} = \text{4.116 mol}\\\\\text{Moles of H$_{2}$O} = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{32.00 g}} = \text{2.191 mol}$

Step 2. Identify the limiting reactant

Calculate the moles of H₂O we can obtain from each reactant.

From NH₃:

The molar ratio of H₂O:NH₃ is 6:4.

$\text{Moles of H$_{2}$O} = \text{4.116 mol NH$_{3}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{4 mol NH$_{3}$}} = \text{6.174 mol H$_{2}$O}$

From O₂:

The molar ratio of H₂O:O₂ is 6:5.

$\text{Moles of H$_{2}$O} = \text{2.191 mol O$_{2}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{5 mol O$_{2}$}} = \text{2.629 mol H$_{2}$O}$

O₂ is the limiting reactant because it gives the smaller amount of H₂O.

Step 3. Calculate the theoretical yield.

$\text{Theor. yield } = \text{2.629 mol H$_{2}$O}\times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{47.4 g H$_{2}$O}\\\\\text{The maximum yield of H$_{2}$O is }\boxed{\textbf{47.4 g}}$

6 0

3 years ago

What do you mean by Latent heat of evaporation! (not vaporisation/fusion) Kindly tell from Science NCERT class 9.

Ne4ueva [31]

Since none answered from Indian NCERT yet, let me give a simple definition from ICSE..
Latent Heat of vapourisation is the heat energy required to convert unit mass of a substance from liquid to vapour state WITHOUT ANY CHANGE IN ITS TEMPERATURE....
hope this helps!

4 0

3 years ago

This step gives an investigation a specific direction or focus A.observation

frozen [14]

The correct answer is c hypothesis

5 0

3 years ago

Read 2 more answers