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fgiga [73]
2 years ago
7

Sir Isaac Newton wrote the equation (d=1/2 gt^2 to determine the distance (d), in meters, an object falls in a given amount of t

ime (t), in seconds. If an object falls for 8 seconds, what is the distance, in meters, it falls?
A. 4g
B. 8g
C. 16g
D. 32g
Mathematics
1 answer:
qwelly [4]2 years ago
3 0

Answer:

D) 32g

Step-by-step explanation:

\displaystyle d=\frac{1}{2}gt^2\\\\d=\frac{1}{2}g(8)^2\\\\d=32g

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17cm per minute = meters per hour
Arlecino [84]
Answer:  10.2 meters per hour; or, write as: 10 ⅕ meters per hour.
___________________________________________
Explanation:
_____________________________________
Note: "h" = time in "hour(s)" ; 
         "cm" = length in "centimeter(s)" ;
         "min" = time in "minute(s)";
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_____________________________________
Note these EXACT conversions:
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100 cm = 1 m ; 
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To solve: 

Given: 17 cm / min ; convert to:  ________ m / h 
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(17 cm / min)* (1 m /100cm) * (60 min / 1 h)  = _______ m / h
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The "cm" units cancel to "1"; the "min" units cancel to "1" and we are left with units of "m/h" {"meters per hour"}.
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We are left with (17 *1 m * 60) / (100 * 1 h) =  [(17 * 60) m] / [100 h] 
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________________________________________________________
To simply: (17 * 60) / 100 ;
_________________________
Method 1):  To simplify: (17 * 60) / 100 ;

→Rewrite as: (17*60) / 100 = (17*20*3)/(20*5) ;  
→Cancel out the "20's "; and rewrite as: 

→ (17*60) / 100 = (17*3)/5 = 51/5 
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________________________________________________________
Method 2) To simplify: (17 * 60) / 100 ; Use calculator (or by hand):
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→ (17 * 60) / 100 = 1,020 /100 
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__________________________________
Method 3) To simplify: (17 * 60) / 100 ;
_____________________________________
→ (17 * 60) / 100 = ? ;  

→ Divide BOTH the "100" AND the "60" by "10";

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____________________________
→ (17*60)/100 = (17*6)/10 = 102/10

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