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Readme [11.4K]
2 years ago
9

Do the tables show a proportional relationship? Mark Yes or No for each. Table A

Mathematics
2 answers:
bekas [8.4K]2 years ago
8 0
Yes yes yes no no yes no yes no no
77julia77 [94]2 years ago
6 0
A. Yes B. yes C.no D. yes E.no
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Rectangle R has varying length l and width w but a constant perimeter of 4 ft. A. Express the area A as a function of l. What do
ivanzaharov [21]
Given:
l = length of the rectangle
w = width of the rectangle
P = 4 ft, constant perimeter

Because the given perimeter is constant,
2(w + l) = 4
w + l = 2
w = 2 - l            (1)

Part A.
The area is
A = w*l 
   = (2 - l)*l
 A  = 2l - l²
This is a quadratic function or a parabola.

Part B.
Write the parabola in standard form.
A = -[l² - 2l]
   = -[ (l -1)² - 1]
   = -(l -1)² + 1
This is a parabola with vertex at (1, 1). Because the leading coefficient is negative the curve is downward, as shown below.

The maximum value occurs at the vertex, so the maximum value of A = 1.
From equation (1), obtain
w = 2 - l = 2 - 1 = 1.
The maximum value of the area occurs when w=1 and l=1 (a square).

Answer:
The area is maximum when l=1 and w=1.
The geometric argument is based on the vertex of the parabola denoting maximum area.

4 0
4 years ago
Which expression is equivalent to 24 ⋅ 2−7?
marta [7]

Answer:

211

Step-by-step explanation:

3 0
3 years ago
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Can some find the the answer than explain it Thank you
STALIN [3.7K]

Answer:

2 week ago so you dont need so free point

Step-by-step explanation:

7 0
3 years ago
Given: f(x)=x^2, g(x)=x+6, h(x)=7<br><br>Find h{g[f(x)]}​
arsen [322]

Step-by-step explanation:

f(x)=x^2,\ g(x)=x+6,\ h(x)=7\\\\h(x)=7\ \text{It's the constant function. Therefore}\ h\{g[f(x)]\}=7

4 0
4 years ago
What is the solution for the equation 5/3b^3-2b^2-5=2/b^3-2
PilotLPTM [1.2K]
I looked it up and it said it was c 
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3 years ago
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