Can anyone help me identify the center & radius pls
1 answer:
Answer:
see explanation
Step-by-step explanation:
the equation of a circle centred at the origin is
x² + y² = r² ( r is the radius )
(11)
- 81 + x² = - y² ( add y² to both sides )
- 81 + x² + y² = 0 ( add 81 to both sides )
x² + y² = 81 ← in standard form
with centre = (0, 0 ) and r = = 9
(12)
y² + x² - 196 = 0 ( add 196 to both sides )
x² + y² = 196 ← in standard form
with centre = (0, 0 ) and r = = 14
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Answer:
P = 0.5Q - 20
Step-by-step explanation:
P = kQ + c
substitute Q = 60 , P = 10 into the equation
10 = 60k + c → (1)
substitute Q = 240, P = 100 into the equation
100 = 240k + c → (2)
subtract (1) from (2) term by term to eliminate c
90 = 180k ( divide both sides by 180 )
=
= 0.5 = k
substitute k = 0.5 into (1) and solve for c
10 = 60(0.5) + c
10 = 30 + c ( subtract 30 from both sides )
- 20 = c
then
P = 0.5Q - 20
We have that
using a graph tool
see the attached figure
the answer is the first option
y<=3x
y>-2x-1
using a graph tool
see the attached figure
the answer is the first option
y<=3x
y>-2x-1