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2 years ago

Find the lowest common denominator of 1/3 and 2/5

Mathematics

1 answer:

Katen [24]2 years ago

5 0

Answer:

The lowest ccommon denominator (or LCD) of 1/3 and 2/5 is 15.

Step-by-step explanation:

The lowest multiple of 3 and 5 is 3*5 = 15.

In terms with the LCD, 1/3 now equals 5/15; and 2/5 now equals 6/15.

Hope this helps :)

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Which of the following represents the top view of the figure? PLZ HURRY

lana [24]

The third one. The one that goes long box, short, short, long. That's because the first box isn't covered, and they next two are about half boxes showing and the last one is a full box again.

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3 years ago

Triangle ABC is similar to DEF.

Schach [20]

Answer:

Step-by-step explanation:

Answer:

1. The scale factor here is 1.5

2. The scale factor here is 2/3

Step-by-step explanation:

Here, we shall be dealing with scales of triangles.

we have two triangles;

ABC and DEF

longest sides are in the ratio;

12 : 8

1. What scale factor translates DEF to ABC?

The ratio of the length can be beaten down to 3:2

So therefore, we can see that by multiplying the sides of of DEF by 1.5, we can arrive at the sides of ABC

So the scale factor here is 1.5

2. This is like the other way round of what we have above.

By multiplying the sides of ABC by 2/3, we shall have the sides of DEF

6 0

3 years ago

Anne's computer is broken. Cal's computer helpers charges a $50 fee plus $25 per hour (h) to fix it. Which expression represent

AnnZ [28]

Answer:

y = 25h + 50

Step-by-step explanation:

Let's say he stayed for two hours.

y = 25(2) + 50

y = 50 + 50

y = 100

7 0

2 years ago

Consider the following equations. f(x) = − 4/ x3, y = 0, x = −2, x = −1. Sketch the region bounded by the graphs of the equation

Sindrei [870]

Answer:

1.5 unit^2

Step-by-step explanation:

Solution:-

- A graphing utility was used to plot the following equations:

$f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2$

- The plot is given in the document attached.

- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).

- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.

We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).

The double integration formulation can be written as:

$A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2$