Answer:
Step-by-step explanation:
9. f(g(-n))
g(-n) = -(n²+5) = -n²-5
f(g(-n)) = 2n+1 (-n²-5 )
2n(-n²-5)+1(-n²-5 )
-2n³-10n-n²-5
-2n³-n²-10n-5
n²(-2n-1) +5(2n-1)
(n²+5)(2n-1)
10. (2x+2)(x³+3)
2x(x³+3)+2(x³+3)
2x⁴ + 2x³ +6x +6
2x³(x+1)+6(x+1)
(2x³+6)(x+1
9514 1404 393
Answer:
- 4 3-point baskets
- 7 2-point baskets
Step-by-step explanation:
Let x represent the number of 2-point baskets Nicoli made. Then (x -3) is the number of 3-point baskets. The total number of points is ...
2x +3(x -3) = 5x -9 = 26
5x = 35 . . . . . . add 9
x = 7 . . . . . . . divide by 5
(x -3) = 4 . . . find the number of 3-point baskets
Jokic made 7 2-point baskets and 4 3-point baskets.
Multiply 5.3 by 104.
Answer: 551.2
Consider the charge for parking one car for t hours.
If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.
If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.
75% is 75/100 or 0.75.
For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be
0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:
3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].
Thus, the function which total parking charge of parking 3 cars for t hours is:
</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1))
Answer: C</span>
Answer:
step-by-step explanation:
You have to solve this to get your answer. This is a case where you have to use the pythagorean theorem.
