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Liono4ka [1.6K]
3 years ago
11

Solve equestion give i give you 20 points​

Mathematics
2 answers:
WARRIOR [948]3 years ago
7 0

Answer:

i cant see everything

Step-by-step explanation:

andre [41]3 years ago
3 0

Answer:

Is that the whole problem

Step-by-step explanation:

or is there more we need to see

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3 years ago
If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?
viktelen [127]

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

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