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GREYUIT [131]
2 years ago
6

Find the sum of the first 9 terms of the geometric sequence: 0.5, 1, 2,-..

Mathematics
1 answer:
yuradex [85]2 years ago
3 0

Answer:

S₉ = 255.5

Step-by-step explanation:

the sum to n terms of a geometric sequence is

S_{n} = \frac{a_{1}(r^{n}-1)  }{r-1}

where a₁ is the first term and r the common ratio

here a₁ = 0.5 and r = \frac{a_{2} }{a_{1} } = \frac{1}{0.5} = 2 , then

S₉ = \frac{0.5(2^{9}-1) }{2-1}

    = \frac{0.5(512-1)}{1}

    = 0.5(511)

    = 255.5

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Answer:

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Step-by-step explanation:

See the diagram of the ramp.

Four men carry 20 boxes each up a ramp as shown.

So, 4 men carry total (4 × 20) = 80 boxes up the ramp and each box weighs 5 pounds.

Then, the 4 men carry total (80 × 5) = 400 lb weight up the ramp.

Now, the vertical height of the ramp from the ground level is 6 ft.

Hence, the muscular work completed by four men will be (400 × 6) = 2400 ft. lbs. (Answer)

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3 years ago
F(n)=4n-3 find the 15th term of the sequence defined by the explicit rule
pickupchik [31]

Answer:

57

Step-by-step explanation:

f(15)=4(15)-3

f(15)=60-3

f(15)=57

Hope that helps, tell me if you need more help

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3 years ago
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If 400 kids went to the amusement park and only 120 came back how many got lost?
LekaFEV [45]

Answer:

280

Step-by-step explanation:

400 - 120=280

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2 years ago
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A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and
goblinko [34]

Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

where;

F= force applied on the spring

x = the extension on the spring

k= the spring constant which varies in spring.

The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

Here the spring extension is 15 m

<u>In spring B</u>

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

<u>Compare</u>

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

=15m-12m=3m

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3 years ago
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