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3 years ago

13

A lemonade stand sells 14 gallons of lemonade in three hours. How many gallons can they expect to sell after three, eight hour d

ays

1 answer:

Alecsey [184]3 years ago

3 0

They should expect to sell 112 gal

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70000 is ten times as much as

svetlana [45]

70,000 is ten times as much as 7,000. This is because 7,000 times 10 equals 70,000. I got this answer by dividing 70,000 by 10.

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2 years ago

Given this function: f ( x )=−2cos(4 πx ) Find the following:

Neporo4naja [7]

Answer:

Period =½

Equation of midline, y=0

Maximum =2

Minimum=-2

Step-by-step explanation:

The given function is

$f(x) = - 2 \cos(4 \pi \: x)$

The period is given by:

$\frac{2\pi}{b} = \frac{2\pi}{4\pi} = \frac{1}{2}$

The equation of the midline is y=0 since there is no vertical shift

The amplitude of this function is 2 so the range is -2≤y≤2.

Hence the maximum value is 2 and minimum value is -2

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3 years ago

How would you lable a math bar model

Anastasy [175]

Well,. you could say bees in hive + bees in garden = bees in total.

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2 years ago

ALGEBRA II HELP :/

elena-14-01-66 [18.8K]

Answer:

18

Step-by-step explanation:

f(x) = x³+4x²-8x-6

P(a) <=> P(x)

-2 | 1 4 -8 -6

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| -2 -4 24

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3 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

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3 years ago