Please help :)

1 answer:

6 0

For a system of equations such as this, add both of the equations together. The d values will cancel each other out, making 2e=-4. This means that e=-2. If you plug this into one of the equations, you will have d + (-2) = 1. Isolate the variable by adding -2 to both sides: d=3. Written in the format described above (d,e), your answer is (3, -2).

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Please help thank you.

Rainbow [258]

A. Given
b. Substituition Property (replaces x with the definition of x=8)
c. Subtraction Property of Equality (-1-88=-89)
d. Division Property of Equality (isolating y)
e. Symmetric Property of Equality (a=b -> b=a)

so the second option

8 0

3 years ago

I need help with this, please!

siniylev [52]

Answer:

The answer to your question is None of the options, the answer is y ≥ 1

Step-by-step explanation:

Inequality

5 - 3 (y + 2) ≤ 6y - 10

1.- Expand

5 - 3y - 6 ≤ 6y - 10

2.- Simplify like terms

-3y - 1 ≤ 6y - 10

3.- Add -6y in both sides

- 3y - 6y - 1 ≤ 6y - 10 - 6y

4.- Simplify

-9y - 1 ≤ -10

5.- Add 1 in both sides

-9y - 1 + 1 ≤ -10 + 1

6.- Simplify

-9y ≤ -9

7.- Divide both sides by -9 and change ≤ by ≥

-9/-9 y ≥ -9/-9

8.- Simplify

y ≥ 1

3 0

2 years ago

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe

Mila [183]

<h3>Answer: 0.1319</h3>

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Work Shown:

$P(x) = (_n C_x)*(p)^x*(1-p)^{n-x}\\\\P(14) = (_{15} C_{14})*(0.8)^{14}*(1-0.8)^{15-14}\\\\P(14) = 15*(0.8)^{14}*(0.2)^{1}\\\\P(14) \approx 0.13194139533312 \\\\P(14) \approx \boldsymbol{0.1319} \\\\$

Side note: you can use the nCr formula to compute $_{15} C_{14}$ ; however, it's much quicker to use the shortcut formula $_{n} C_{n-1} = n$ . You can also use Pascal's Triangle to find the value of $_{15} C_{14}$