Answer:
I do't know how to solve this.
Step-by-step explanation:
Answer:
2<x<4/3
Step-by-step explanation:
Given the equation of a graph to be y = |3x− 5|, if the equation is one unit to the right, this can be expressed as |3x-5| > 1.
Solving the resulting equation
|3x-5| > 1.
Since the function 3x-5 is in a modulus sign, this means that the function can take both negative and positive values.
For positive value of the function;
+(3x-5) > 1
3x > 1+5
3x>6
x>6/3
x>2 ... (1)
For the negative value of the function;
-(3x-5) > 1
On expansion
-3x+5 > 1
-3x > 1-5
-3x > -4
Multiplying through by -1 will also change the inequality sign
x < -4/-3
x < 4/3...(2)
Combining equation 1 and 2, we have;
2<x<4/3
If - 1 is a zero then

is a factor.
Dividing with this factor using the long division approach, we get the quadratic factor to be,

(see attachment).
We can rewrite the polynomial as

We can further factor as

That is
Simplify both sides of the equation
-25(x-4)=-55(x-10)
(-25)(x) + (-25)(-4)=(-55)(x) + (-55) (-10)
Distribute
-25x+100=-55x+550
Add 55x to both sides
-25x+100+55x=-55x+550+55x
30x+100-100=550-100
subtract 100 from both sides
30x+100-100=550-100
30x=450
divide both sides by 30
30x/30=450/30
x= 15
The value of x is 15
I hope that's help you my friend !
Answer: -13
Step-by-step explanation:
c-2y
= -5-2(4)
= -5 - 8
= -13