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seraphim [82]
2 years ago
7

Priscilla started a part time job working at an after school program.

Mathematics
1 answer:
pav-90 [236]2 years ago
4 0

Answer:

B

Step-by-step explanation:

The first week, she worked

3  \times 2\frac{1}{2}  = 3 \times  \frac{5}{2}  = \frac{15}{2}

The second week, she worked

3 \times 2 \frac{1}{4}  = 3 \times  \frac{9}{4}  =  \frac{27}{4}

Total number of hours she worked over these 6 days

\frac{15}{2}  +  \frac{27}{4}  =  \frac{57}{4}  =  14\frac{1}{4}

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Which of these objects have reflectional symmetry (or approximate reflectional symmetry)
Mnenie [13.5K]

Answer:

Objects having reflectional symmetry (or approximate reflectional symmetry) are-

a.

b.

d.

e.

6 0
3 years ago
Which fraction is between -5/8 and -1/2​
Rzqust [24]

Answer:

The answer is −1.125...

Step-by-step explanation:

Hope this helps! :)

6 0
3 years ago
A rectangle has a length that is 5 inches greater than its width, and its area is 104 square inches. The equation (x + 5)x = 104
mina [271]
1. Regroup terms
x(x+5)=104

2. Expand
x^2+5x=104

3. Move all terms to one side
x^2+5x-104=0

4. Factor x^2+5x-104
(x-8)(x+13)=0

5. Solve for x
x=8 or x=-13
Since x<0 is not possible in this case, x=8

6. Finding the dimensions
We know that one side has to be x+5, and now that we know x:
8+5=13
13*8=104

The dimensions are 13 and 8, have a nice day :D
8 0
3 years ago
Read 2 more answers
Solve for b .<br><br> -9 b = 27<br><br> b =
saul85 [17]

Final Answer: b = -3

Steps/Reasons/Explanation:

Question: Solve for b. -9 b = 27. b = ?

<u>Step 1</u>: Divide both sides by -9.

b = -\frac{27}{9}

<u>Step 2</u>: Simplify \frac{27}{9} to 3.

b = -3

~I hope I helped you :)~

5 0
2 years ago
Read 2 more answers
Determine whether the given relation is an implicit solution to the given differential equation. assume that y is a function of
Xelga [282]
Differentiate:x^2 + y^2 = 4 
You get this:2x + 2yy' = 0 
bring the x variable on the other side:2yy' = -2x 
Now divide 2y to leave y' by itself:y' = -2x/2y 
Answer: y' = -x/y 
The given relation is not a implicit solution to the given differential equation.
6 0
3 years ago
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