FIRST FIND THE THE FIRST AND SECOND DIFFERENCES ON THE GIVEN SEQUENCE OF NUMBERS. FOR EXAMPLE IF YOU ARE GIVEN THIS SEQUENCE 2,4,6,8............AND YOU ARE ASKED TO FIND THE GENERAL FORMULA.... STEP 1:FIND THE FIRST DIFFERENCE BY SUBTRACTING THE FIRST TERM FROM THE SECOND TERM,AND THE SECOND FROM THE THIRD AND SO ON. STEP 2:FIND THE SECOND DIFFERENCE BY APPLYING STEP 1 TO THE ANSWERS OBTAINED.EG 4-2=2,6-4=2,8-6=2 THEREFORE THE SECOND DIFFERENCE WILL BE 2-2=0,2-2=0 STEP 3:DIVIDE THE SECOND DIFFERENCE BY 2 TO GET THE VALUE OF (A). STEP 4:WRITE 3a-b=the first term of the first term of the first difference which is the difference between 4 and 2.and solve for the value of b.3(0)-b=2 therefore b=-2 STEP 5:FIND THE VALUE OF c BY term 1=a=b=c
The coordinate of the vertex is; (h, k) = (3, -5)
The final equation of the parabola is; y = 5(x - 3)² - 5
<h3>How to find the vertex of a Parabola?</h3>
The vertex is the coordinate of the crest or trough of the curve. Now, in the given graph, we only have a Trough which is the lowest point of the graph.
The coordinate of the vertex is; (h, k) = (3, -5)
2) Since the general equation is;
y = a(x - h)² + k
We will have;
y = a(x - 3)² - 5
At x = 2, y = 0. Thus;
0 = a(2 - 3)² - 5
a - 5 = 0
a = 5
3) The final equation of the parabola is;
y = 5(x - 3)² - 5
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Answer:
Dude the picture is really blurry
Step-by-step explanation:
The table of possible values when graphing
X Y
-2 9
-1 5
0 1
1 -3
2 -7
The intercepts x (1/4,0) and y (0,1)