n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Answer:
the answer would be 80 :)
3.24m
the longest piece will be associated with 8 parts of the ratio.
divide 144 by 8 to find 1 part of the ration then multiply this value by 6 and 4 for the remaining parts of the ratio
= 18 cm ← 1 part
6 parts = 6 × 18 = 108 cm
4 parts = 4 × 18 = 72 cm
length = 144 + 108 + 72 = 324 cm = 3.24m
