Question

A population is in Hardy-Weinberg equilibrium at a locus with two alleles, A and a, each with a frequency of 0.5. A is completely dominant over the recessive a. Suddenly, the environment changes where now individuals with the dominant phenotype only have a 0.50 chance of survival while the recessive phenotypes all survive. What are the genotype frequencies (using decimal numbers, e.g. 0.10) in the surviving population after this selection event

Answer 1

From the Hardy-Weinberg equilibrium, the genotype frequencies in the surviving population after this selection event is A = 0.25, and a = 0.75.

What is the Hardy-Weinberg equilibrium?

The Hardy-Weinberg equilibrium describe the equilibrium which exists between the alleles of a species of organism when no external forces are acting on the population.

In Hardy-Weinberg equilibrium, the sum of allele frequencies is 1.

The allele frequencies for A and a are each = 0.5: therefore, A + a = 1

When the chances of survival of A is 0.5 and a = 1

Frequency of A = 0.5 × 0.5 = 0.25

Then a = 1 - 0.25 = 0.75

Therefore, the genotype frequencies in the surviving population after this selection event is A = 0.25, and a = 0.75.

Learn more about Hardy-Weinberg equilibrium at: brainly.com/question/3406634

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