Answer:
Frequency, f = 3.73Hz
Explanation:
The frequency of a simple harmonic 6is given by:
f = w/2pi
But w= Sqrt( k/m)
Where k is the spring constant
And m is the mass
Given:
Mass=0.20kg
Spring constant, k=130N/m
w= Sqrt(130/0.20)
w= Sqrt(650)
w= 25.50 m
Frequency, f = w/2pi
f = 25.50/(2×3.142)
f = 3.73Hz
Answer:
Final velocity v = 8.944 m/sec
Explanation:
We have given distance S = 40 meters
Time t = 10 sec
As it starts from rest so initial velocity u = 0
From second equation of motion 


Now from first equation of motion
, here v is final velocity, u is initial velocity, a is acceleration and t is time
So 
Answer:
1) The speed of sound increases
2) 440 Hz
3) 29°C
4) 17°C
5) 434 Hz
6) 12 m/s
7) 17.3 m
Explanation:
1) The speed of sound increases
2) V = f×λ
f = V/λ = 343/0.78 = 439.744 ≈ 440 Hz
3) V = f×λ
512 × 0.68 = 348.16 m/s
348.16 - 331 = 17.16
T = 17.16/0.6 = 28.6 ≈ 29°C
4) Increase in speed = 350 - 340 = 10
Increase in temperature = 10/0.6 = 16.67° ≈ 17°C
5) f = V/λ = 343/0.79 = 434 Hz
6) 331 + 0.6×30 - (331 × 0.6 ×10) = 12 m/s
7) V = 331 + 0.6×25 = 346m/s
λ = 346/20 = 17.3 m