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zaharov [31]
3 years ago
13

Which of the following is a derived unit? ampere newton second kilogram

Physics
1 answer:
Soloha48 [4]3 years ago
5 0

Newton is your answer.

ampere, second, kilograms, are all base units.

hope this helps

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To get up on the roof, a person (mass 70.0kg) places a 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad
Julli [10]

The magnitude of the forces acting at the top are;

\mathbf{F_{Top, \ x}} = 132.95 N

\mathbf{F_{Top, \ y}} = 0

The magnitude of the forces acting at the bottom are;

\mathbf{F_{Bottom, \ x}} = \mathbf{ F_f} = -132.95 N

\mathbf{F_{Bottom, \ y}} = 784.8 N

The known parameters in the question are;

The mass of the person, m₁ = 70.0 kg

The length of the ladder, l = 6.00 m

The mass of the ladder, m₂ = 10.0 kg

The distance of the base of the ladder from the house, d = 2.00 m

The point on the roof the ladder rests = A frictionless plastic rain gutter

The location of the center of mass of the ladder, C.M. = 2 m from the bottom of the ladder

The location of the point the person is standing = 3 meters from the bottom

g = The acceleration due to gravity ≈ 9.81 m/s²

The required parameters are;

The magnitudes of the forces on the ladder at the top and bottom

The strategy to be used;

Find the angle of inclination of the ladder, θ

At equilibrium, the sum of the moments about a point is zero

The angle of inclination of the ladder, θ = arccos(2/6) ≈ 70.53 °C

Taking moment about the point of contact of the ladder with the ground, <em>B </em>gives;

\sum M_B = 0

Therefore;

\sum M_{BCW} = \sum M_{BCCW}

Where;

\sum M_{BCW} = The sum of clockwise moments about <em>B</em>

\sum M_{BCCW} = The sum of counterclockwise moments about <em>B</em>

Therefore, we have;

\sum M_{BCW} = 2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81

\sum M_{BCCW} = F_R × √(6² - 2²)

Therefore, we get;

2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81  = F_R × √(6² - 2²)

F_R  = (2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81)/(√(6² - 2²)) ≈ 132.95

The reaction force on the wall, F_R ≈ 132.95 N

We note that the magnitude of the reaction force at the roof, F_R = The magnitude of the frictional force of bottom of the ladder on the floor, F_f but opposite in direction

Therefore;

F_R = -F_f

F_f = - F_R ≈ -132.95 N

Similarly, at equilibrium, we have;

∑Fₓ = \sum F_y = 0

The vertical component of the forces acting on the ladder are, (taking forces acting upward as positive;

\sum F_y = -70.0 × 9.81 - 10 × 9.81 + F_{By}

∴ The upward force acting at the bottom, F_{By} = 784.8 N

Therefore;

The magnitudes of the forces at the ladder top and bottom are;

At the top;

\mathbf{F_{Top, \ x}} = F_R ≈ 132.95 N←

\mathbf{F_{Top, \ y}} = 0 (The surface upon which the ladder rest at the top is frictionless)

At the bottom;

\mathbf{F_{Bottom, \ x}} = F_f ≈ -132.95 N →

\mathbf{F_{Bottom, \ y}} = F_{By} = 784.8 N ↑

Learn more about equilibrium of forces here;

brainly.com/question/16051313

8 0
3 years ago
What is the radius of a force?
vazorg [7]

Answer:

this kind of force is proportional directly to the speed of the object and inversely to the radius of the curved path. Therefore, Hence, the force becomes 2.25 times the original force.

Explanation:

6 0
2 years ago
When on object’s spectral lines are shifted from their rest wavelengths to longer wavelengths, we say that the object’s spectrum
neonofarm [45]

Answer:

Both statements are true.

Explanation:

When a celestial object (stars, galaxies) is moving away from an observer its spectral lines¹ will be shifted to the red part of the spectrum² (longer wavelength), in the other hand if the celestial body is moving toward the observer, the spectral lines will be shifted to the blue part of the spectrum (shorter wavelength). That is known as the Doppler shift.

This Doppler shift can be explained with the Doppler Effect³, which is defined for the case of light as:    

\frac{\Delta \lambda}{\lambda_{0}} = \frac{v}{c}    (1)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the rest wavelength, v is the velocity of the source and c is the speed of light.

This redshift in distant galaxies is a strong evidence for the expansion of the universe. Equation 1 also allows the measurement of radial velocity from celestial objects.  

Summary:  

Blueshift:

\lambda

Redshift:

\lambda >\lambda_{0}

¹Spectral lines: Determines the presence of particular elements in the photosphere of an star.

²Spectrum: Decomposition of light in its characteristic colors (wavelengths).

³Doppler Effect: Change in the frequency of a wave as a consequence of the movement from a source relative to an observer or vice versa.

4 0
4 years ago
Which logic function(s) provides a high output in response to only seven low inputs?
inysia [295]

Answer:

figuer it out we are all on our ownExplanation:

3 0
4 years ago
The unit J/Pa is equivalent to<br><br>(a) m³<br><br>(b) cm³<br><br>(c) dm³<br><br>(d) None of these​
Karolina [17]

Answer:

(a) m³

Explanation:

Joule is the unit of work and Pascal is unit of pressure.

J/Pa = work/pressure = Nm/Nm⁻² = m³

Thus, The unit J/Pa is equivalent to m³

<u>-TheUnknownScientist</u>

5 0
3 years ago
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