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Inessa [10]
2 years ago
12

A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the c

ar? Group of answer choices 1500 N 1750 N 2750 N 3000 N
Physics
1 answer:
lukranit [14]2 years ago
4 0

The frictional force exerted by the road on the car is 3000N

Given the mass of the car is 1000 kg , the velocity of the car is 20m/s

and the time is 6.6s

We need to find the frictional force exerted by the road on the car

We know that Force = mass * acceleration

Now here Mass is given but acceleration is not given

So, we will find acceleration by using the formula v = u+at

Where u = 0

v = 20m/s

a = ?

t = 6.6

Substitute the values in the formula We get

v = u+at

20 = 0+(a)(6.6)

20/6.6 = a

∴ a = 3.03 m/s^2

Rounding to nearest tenth is 3m/s^2

Hence the acceleration is 3m/s^2

Now substituting the value of acceleration in F = ma

Where m = mass

a = acceleration

F = 1000*3

∴ F = 3000N

Hence the frictional force exerted by the road on the car is 3000 N

Learn more about Frictional force here

brainly.com/question/23161460

#SPJ4

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Explanation:

From the question we are told that

   The mass density is  \mu =\frac{m}{L}  = 1.17 \ g/cm =0.117 kg/m

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Generally the magnetic force acting on the wire is mathematically represented as

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Here   F_F is the frictional  force which is mathematically represented as

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While F_B  is the magnetic force which is mathematically represented as

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Here \theta =90^o is the angle between the direction of the force and that of the current

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      BIL  =  \mu_k * m * g

=>   B  =  \mu_k *  \frac{m}{L} * [\frac{g}{I} ]

=>   B  =  0.25 *  0.117  * [\frac{9.8}{1.24} ]

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Apply the right hand curling rule , the thumb pointing towards that direction of the current we see that the direction of the magnetic field is into the surface as shown on the first uploaded image

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